Question

A keen ten-pin bowler plays five rounds in one evening. His scores are
$98,64,103,108$and$109$. Which average (mode, mean, or median) will he choose to report to
his friends at the end of the evening? Explain your answer carefully, showing all your
calculations clearly.

Answer 1

Hint: First define the types of average; mean, mode, and median. Then define which one is
appropriate to report to the friend. Then use that method to find the average score.
It is given that keen ten-pin bowler plays five rounds in one evening and his scores are
$98,64,103,108$and$109$.
We have to tell that which type of average will be chosen to report his friend at the end of the
evening.
There are three types of averages named as mode, mean, or median.

The mode gave the data whose frequency is higher and who is most appeared. The scores given
to us has one frequency of each score, so it is not the proper way to report to the friend at the end
of the evening.
The median is also a type of average which gives the central tendency of the given data. It gives
the value of the data, whose value is at the center of the data. It can also be used to report.
Mean gives us the general value of the data, which is the approximate value of each score. In
other words, we can say that mean gives us the general central tendency of the data.
Thus, it is a better way to report to the friend at the end of the evening.
Given scores: - $98,64,103,108$and$109$
Then the average (Mean) is given as:
Average$ = \dfrac{{{\text{Sum of scores}}}}{{{\text{Number of Round played}}}}$

Average$ = \dfrac{{98 + 64 + 103 + 108 + 109}}{5}$

Average$ = \dfrac{{482}}{5}$
Average$ = 96.4$
So, the average score of the pin bowler is$96.4$.

Note: There are three types of average- mean, mode, and median. In which, we need some
calculation in case of mean and mode but in the case of the median, we need the analysis of the
given data to find the average.