Question

A granary is in the shape of a cuboid of size \[8 \times 6 \times 3\] $m$. If a bag of grain occupies a space of \[0.65\] ${m^3}$, how many bags can store in the granary?

Answer 1

Hint: At first, we are going to find the volume of the granary. Using this volume we will find the number of bags.

Complete step-by-step answer:
It is given that: a granary is in the shape of a cuboid of size \[8 \times 6 \times 3\] $m$. It means the length, width and the height of the granary are \[8m,{\text{ }}6m,{\text{ }}3m\] respectively.
A bag of grain occupies a space of \[0.65\] ${m^3}$.
We know that, if the length, width and the height of the granary is \[l,b,h\] respectively, then the volume of cuboid is given by the formula \[l \times b \times h\]
Let us substitute the value of \[l,b,h\] in the volume of cuboid formula, we get,
The volume of the granary as \[8 \times 6 \times 3\] ${m^3}$.
To find the total number of bags we must divide the volume of granary by the volume occupied by a bag of grains.
So, the number of bags in the granary is \[ = \dfrac{{8 \times 6 \times 3}}{{0.65}} = 221.5\]
It implies that the number of bags that can be stored in the granary is \[221\].
Hence, \[221\] bags can be stored in the granary of size \[8 \times 6 \times 3\]m.

Note: We can solve this sum in another way.
Let us take the number of bags to be \[n\].
So, the volume of \[n\] number of bags \[0.65n\].
As per the problem we get,
\[0.65n = 8 \times 6 \times 3\]
Solving we get,
\[n = \dfrac{{8 \times 6 \times 3}}{{0.65}}\]
Solving we get,
\[n = 221.5 \approx 221\]
Hence, \[221\] bags can be stored in the granary.