A gas undergoes a process in which its pressure \[P\] and volume \[V\] are related as \[V{P^n} = {\text{constant}}\]. The bulk modulus of the gas in the process is
A. \[nP\]
B. \[{P^{1/n}}\]
C. \[P/n\]
D. \[{P^n}\]
Answer
602.7k+ views
Hint:Use the formula for bulk modulus for the material of an object. This formula gives the relation between the change in pressure on the object, original volume of the object and change in volume of the object. Differentiate the given relation between the pressure and volume of the gas in the process and determine the bulk modulus of the gas in the process.
Formula used:
The bulk modulus \[\beta \] of material of an object is given by the formula
\[\beta = - \dfrac{{VdP}}{{dV}}\] …… (1)
Here, \[V\] is the original volume of the object, \[dV\] is the change in volume of the object and \[dP\] is the change in pressure on the object.
Complete step by step answer:
We have given that the pressure of the gas is \[P\] and volume of the gas is \[V\].
We have also given that the pressure and volume of the gas in the process are related as
\[V{P^n} = {\text{constant}}\]
Let us differentiate the above relation with respect to volume.
\[\dfrac{d}{{dV}}\left( {V{P^n}} \right) = 0\]
\[ \Rightarrow {P^n}\dfrac{{dV}}{{dV}} + V\dfrac{{d{P^n}}}{{dV}} = 0\]
We cannot differentiate the second term in the above expression. Let us use chain rule for the differentiation of the second term in the above equation.
\[ \Rightarrow {P^n}\left( 1 \right) + V\dfrac{{d{P^n}}}{{dP}}\dfrac{{dP}}{{dV}} = 0\]
\[ \Rightarrow {P^n} + Vn{P^{n - 1}}\dfrac{{dP}}{{dP}}\dfrac{{dP}}{{dV}} = 0\]
\[ \Rightarrow {P^n} + Vn{P^{n - 1}}\left( 1 \right)\dfrac{{dP}}{{dV}} = 0\]
\[ \Rightarrow {P^{n - 1}}\left( {P + nV\dfrac{{dP}}{{dV}}} \right) = 0\]
\[ \Rightarrow nV\dfrac{{dP}}{{dV}} = - P\]
\[ \therefore V\dfrac{{dP}}{{dV}} = - \dfrac{P}{n}\]
Substitute \[ - \beta \] for \[V\dfrac{{dP}}{{dV}}\] in the above equation.
\[ \Rightarrow - \beta = - \dfrac{P}{n}\]
\[ \therefore \beta = \dfrac{P}{n}\]
Therefore, the bulk modulus for the gas in the process is \[\dfrac{P}{n}\].
Hence, the correct option is C.
Note:In general, we use the formula for the bulk modulus of the material of an object with the positive sign. But actually the formula for the bulk modulus of material of an object includes a negative sign showing that the volume of the object decreases when the pressure is applied on it. Hence, the students should not forget to use this negative sign in the formula for bulk modulus. Otherwise, we will end with the same expression for bulk modulus of the gas in the process but with negative sign which is not in any of the options given.
Formula used:
The bulk modulus \[\beta \] of material of an object is given by the formula
\[\beta = - \dfrac{{VdP}}{{dV}}\] …… (1)
Here, \[V\] is the original volume of the object, \[dV\] is the change in volume of the object and \[dP\] is the change in pressure on the object.
Complete step by step answer:
We have given that the pressure of the gas is \[P\] and volume of the gas is \[V\].
We have also given that the pressure and volume of the gas in the process are related as
\[V{P^n} = {\text{constant}}\]
Let us differentiate the above relation with respect to volume.
\[\dfrac{d}{{dV}}\left( {V{P^n}} \right) = 0\]
\[ \Rightarrow {P^n}\dfrac{{dV}}{{dV}} + V\dfrac{{d{P^n}}}{{dV}} = 0\]
We cannot differentiate the second term in the above expression. Let us use chain rule for the differentiation of the second term in the above equation.
\[ \Rightarrow {P^n}\left( 1 \right) + V\dfrac{{d{P^n}}}{{dP}}\dfrac{{dP}}{{dV}} = 0\]
\[ \Rightarrow {P^n} + Vn{P^{n - 1}}\dfrac{{dP}}{{dP}}\dfrac{{dP}}{{dV}} = 0\]
\[ \Rightarrow {P^n} + Vn{P^{n - 1}}\left( 1 \right)\dfrac{{dP}}{{dV}} = 0\]
\[ \Rightarrow {P^{n - 1}}\left( {P + nV\dfrac{{dP}}{{dV}}} \right) = 0\]
\[ \Rightarrow nV\dfrac{{dP}}{{dV}} = - P\]
\[ \therefore V\dfrac{{dP}}{{dV}} = - \dfrac{P}{n}\]
Substitute \[ - \beta \] for \[V\dfrac{{dP}}{{dV}}\] in the above equation.
\[ \Rightarrow - \beta = - \dfrac{P}{n}\]
\[ \therefore \beta = \dfrac{P}{n}\]
Therefore, the bulk modulus for the gas in the process is \[\dfrac{P}{n}\].
Hence, the correct option is C.
Note:In general, we use the formula for the bulk modulus of the material of an object with the positive sign. But actually the formula for the bulk modulus of material of an object includes a negative sign showing that the volume of the object decreases when the pressure is applied on it. Hence, the students should not forget to use this negative sign in the formula for bulk modulus. Otherwise, we will end with the same expression for bulk modulus of the gas in the process but with negative sign which is not in any of the options given.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

What are hard magnetic materials class 11 physics CBSE

