Question

A fruit vendor sells fruits from his shop. Selling prices of apple, mango and orange are \[Rs.20,{\text{ }}Rs.10{\text{ }} and {\text{ }}Rs.5\] each respectively. The sales in three days are given below.

Day	Apples	Mangoes	Oranges
1	50	60	30
2	40	70	20
3	60	40	10

Write the matrix indicating the total amount collected on each day and hence find the total amount collected from selling of all three fruits combined.

Answer 1

Hint:In the given question we have to find out the matrix indicating par day then finding the total selling of all fruits combined. In the question. Given the price of each apple, mango and orange. In the matrix, given, the number of fruits sold per day. Multiply the prices with the number of fruits according to the information and simply, make a matrix of selling par day. At last all the prices of three days, it is the total selling amount of fruits.

Complete step-by-step answer:
According to question,
Price of each Apple = \[20\]
On 1st day –
No. of Apple = \[50\] & price of 50 apples = \[50 \times 20 = 1000\]
On 2nd day –
     No of Apples = $40$$40$ & Price of 40 apples = $40 \times 20 = 800$
3rd day –
     No of Apples = $60$ , Price of $60$ apples = $60 \times 20 = 1200$
Similarly –
Price of each Mango = $10$
$\therefore $ No. of mangoes in 1st, 2nd and 3rd days respectively are \[60,{\text{ }}70,{\text{ }}40\].
$\therefore $Price of Mangoes in these three days \[ = \left( {60 \times 10} \right),\left( {70 \times 10} \right),\left( {40 \times 10} \right)\]
And $ = 600,700,400$ respectively
Price of each orange –
$\therefore $No of orange sold in 3 days are 30, 20, 10 respectively and their prices are
$\left( {30 \times 5} \right),\left( {20 \times 5} \right),\left( {10 \times 5} \right) = 150,100,50$
$\therefore $ Matrix of fruits sold per day –
\[\left[ {
  Total\;amount\;of\;Apple,Mango,\& Oranges\;in\;1st\;day \\
  Total\;amount\;in\;2nd\;day \\
  Total\;amount\;in\;3rd\;day \\
} \right]\]
$ = \left[ {\begin{array}{*{20}{c}}
  {1000 + 600 + 150} \\
  {800 + 700 + 100} \\
  {1200 + 400 + 50}
\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}
  {1750} \\
  {1600} \\
  {1650}
\end{array}} \right]$
Therefore, $\left[ {\begin{array}{*{20}{c}}
  {1750} \\
  {1600} \\
  {1650}
\end{array}} \right]$ is the required matrix
Total amount wheeled in selling these fruits in all their days are $\left( {1750 + 1600 + 1650} \right) = \left( {6000} \right) = 6000Rs$

Note:Most important step of this numerical is to attentively read & understand the question of what they have asked for. This is a question asked from data collection. Individual prices are given and data of no of fruits sold per day have been given. You have to just find out the total prices of fruits. It can be solved by using unitary method and addition. Calculations should be done very carefully to avoid silly mistakes instead of knowing the whole procedure to solve it.