Question

A fruit seller had some apples. He sells 40% apples and still has 420 apples. So, what will be the number of apple fruit sellers originally had?
A. 588 apples
B. 600 apples
C. 672 apples
D. 700 apples

Answer 1

Hint: Let’s find what will be the percentage of apples left with the shopkeeper, then we assume that the number of apples the shopkeeper originally had is x. After that we apply a percentage formula to find the number of apples left and then compare that with the given value of apples left. This will be the efficient way to find the value of x.

Complete step-by-step answer:

Let the original number of apple shopkeepers be x.

Then as we know that it is given in the question that the shopkeeper had sold 40% apples.

So, this means that he was left with 60% of the original number of apples.
And it is given that the shopkeeper had still 420 apples.

So, 420 = 60% of x.

Now as we know that according to percentage formula A% of B is y.

Then y = \[\dfrac{{\text{A}}}{{{\text{100}}}} \times {\text{B}}\].

So, applying the percentage formula. We get,
420 = \[\dfrac{{60}}{{{\text{100}}}} \times ({\text{x}})\]

So, now we have to solve the above equation to get the value of x.

So, multiplying both sides of the above equation by \[\dfrac{{100}}{{60}}\]. We get,
x = 420*\[\dfrac{{100}}{{60}}\] = 700

So, the original number of apples the shopkeeper had will be equal to 700.

Hence, the correct option will be D.

Note: As you have learned now how to calculate profit as well as loss and also the percentage of them. Here are some tricks or formulas to solve maths problems based on gain and loss.
1. When there are two successful profits say M% and N%, then the net percentage profit equals to (M+N+MN)/100
2. When the profit is M% and loss is N%, then the net % profit or loss will be: (M-N-MN)/100
3. If a product is sold at M% profit and then again sold at N% profit then the actual cost price of the product will be: CP = [100 x 100 x P/(100+M)(100+N)]. In case of loss, CP = [100 x 100 x P/(100-M)(100-N)]