
A force of 150N produces an acceleration of $2m{s^{ - 2}}$ in a body and a force of 200N produces an acceleration of $3m{s^{ - 2}}$. The mass of the body and the coefficient of kinetic friction are
A. 50kg;0.1
B. 25kg;0.1
C. 50kg;0.5
D. 50kg;0.2
Answer
461.7k+ views
Hint: Friction: Friction force is a force which works opposite of applied force. In which friction is working between two surfaces, sliding or rolling. There are two types of friction:
A. Static friction
B. Kinetic friction
Complete step by step answer:
Kinetic friction: The friction which is work on moving objects is known as kinetic friction.
Given in question,
\[{F_1} = 150N\]
\[{a_1} = 2m{s^{ - 2}}\]
\[{F_2} = 200N\]
\[{a_2} = 3m{s^{ - 2}}\]
\[g = 10m{s^{ - 2}}\]
Find,
m= ?
$\mu $=?
According newton's second law with friction,
$ma = F - \mu mg$ …(1)
Put the value in equation 1,
$m \times 2 = 150 - 10\mu m$ …(2)
$m \times 3 = 200 - 10\mu m$ …(3)
Subtracting equation 2 from equation 3
\[
m \times 3 = 200 - 10\mu m \\
\underline {m \times 2 = 150 - 10\mu m} \\
m = 50 \\
\]
Put the value of $m = 50$ in equation 2
$50 \times 3 = 200 - 10 \times 50\mu $
$500\mu = 200 - 150$
$500\mu = 50$
$\mu = \dfrac{{50}}{{500}}$
$\mu = 0.1$
So, the correct answer is “Option A”.
Note: Static friction is working on the object which is on rest while the kinetic friction is working on motion. Friction is equal and opposite of applied force.
A. Static friction
B. Kinetic friction
Complete step by step answer:
Kinetic friction: The friction which is work on moving objects is known as kinetic friction.
Given in question,
\[{F_1} = 150N\]
\[{a_1} = 2m{s^{ - 2}}\]
\[{F_2} = 200N\]
\[{a_2} = 3m{s^{ - 2}}\]
\[g = 10m{s^{ - 2}}\]
Find,
m= ?
$\mu $=?
According newton's second law with friction,
$ma = F - \mu mg$ …(1)
Put the value in equation 1,
$m \times 2 = 150 - 10\mu m$ …(2)
$m \times 3 = 200 - 10\mu m$ …(3)
Subtracting equation 2 from equation 3
\[
m \times 3 = 200 - 10\mu m \\
\underline {m \times 2 = 150 - 10\mu m} \\
m = 50 \\
\]
Put the value of $m = 50$ in equation 2
$50 \times 3 = 200 - 10 \times 50\mu $
$500\mu = 200 - 150$
$500\mu = 50$
$\mu = \dfrac{{50}}{{500}}$
$\mu = 0.1$
So, the correct answer is “Option A”.
Note: Static friction is working on the object which is on rest while the kinetic friction is working on motion. Friction is equal and opposite of applied force.
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