
A first order reaction has a rate constant $1.15 \times {10^{ - 3}}{s^{ - 1}}$. How long will 5 g of this reactant take to reduce to 3 g?
(A) 444 s
(B) 400 s
(C) 528 s
(D) 669 s
Answer
570.6k+ views
Hint: The reaction is called first order reaction when Rate of reaction depends upon concentration of one reactant only.
Example:
$2{H_2}{O_{2(g)}} \to 2{H_2}{O_{(l)}} + {O_2}$
Rate$ = k[{H_2}{O_2}]$
This reaction is first order because Rate of reaction is the first power of ${H_2}{O_2}$ concentration.
Formula used: $t = \dfrac{{2.303}}{k}{\log _{10}}\dfrac{{{A_o}}}{{{A_t}}}$
Complete step by step answer:
As the reaction is first order reaction therefore formula used is
$t = \dfrac{{2.303}}{k}{\log _{10}}\dfrac{{{A_o}}}{{{A_t}}}$______(1)
Where,
t = time
k = Rate constant of first order reaction
${A_o}$ = Initial concentration
${A_t}$ = Final concentration
The values are
$k = 1.15 \times {10^{ - 3}}{s^{ - 1}}$
${A_o} = 5gm$
${A_t} = 3gm$
$t = ?$
Substituting this values in equation number (1) we get
$t = \dfrac{{2.303}}{{1.15 \times {{10}^{ - 3}}}}\log \dfrac{5}{3}$
$t = \dfrac{{2.303}}{{1.15 \times {{10}^{ - 3}}}}\log 1.66$
Value of $\log 1.66 = 0.22$
Putting this value we have $t = \dfrac{{2.303}}{{1.15 \times {{10}^{ - 3}}}} \times \dfrac{{0.22}}{1}$
$t = \dfrac{{2.303 \times 0.22 \times {{10}^3}}}{{1.55}}$
$t = \dfrac{{506.66}}{{1.55}}$
$t = 440.57\sec .$
Therefore, from the above explanation the correct option is (A) 444 s.
Additional information: Overall order of reaction is the sum of the exponent to which concentration terms in the rate law are raised.
Let us consider a reaction.
$aA + bB \to cA + dD$
Here the number of molecules of A reacts with the B molecule.
The order of reaction is not related to the stoichiometric equation of reaction.
It means order of reaction is not equal to = a + b
It is an experimentally determined quantity.
Note: The reaction order is always defined in terms of the concentration of reactant and not of product.
Rate constant for first order depends only on time not concentration reactant.
Example:
$2{H_2}{O_{2(g)}} \to 2{H_2}{O_{(l)}} + {O_2}$
Rate$ = k[{H_2}{O_2}]$
This reaction is first order because Rate of reaction is the first power of ${H_2}{O_2}$ concentration.
Formula used: $t = \dfrac{{2.303}}{k}{\log _{10}}\dfrac{{{A_o}}}{{{A_t}}}$
Complete step by step answer:
As the reaction is first order reaction therefore formula used is
$t = \dfrac{{2.303}}{k}{\log _{10}}\dfrac{{{A_o}}}{{{A_t}}}$______(1)
Where,
t = time
k = Rate constant of first order reaction
${A_o}$ = Initial concentration
${A_t}$ = Final concentration
The values are
$k = 1.15 \times {10^{ - 3}}{s^{ - 1}}$
${A_o} = 5gm$
${A_t} = 3gm$
$t = ?$
Substituting this values in equation number (1) we get
$t = \dfrac{{2.303}}{{1.15 \times {{10}^{ - 3}}}}\log \dfrac{5}{3}$
$t = \dfrac{{2.303}}{{1.15 \times {{10}^{ - 3}}}}\log 1.66$
Value of $\log 1.66 = 0.22$
Putting this value we have $t = \dfrac{{2.303}}{{1.15 \times {{10}^{ - 3}}}} \times \dfrac{{0.22}}{1}$
$t = \dfrac{{2.303 \times 0.22 \times {{10}^3}}}{{1.55}}$
$t = \dfrac{{506.66}}{{1.55}}$
$t = 440.57\sec .$
Therefore, from the above explanation the correct option is (A) 444 s.
Additional information: Overall order of reaction is the sum of the exponent to which concentration terms in the rate law are raised.
Let us consider a reaction.
$aA + bB \to cA + dD$
Here the number of molecules of A reacts with the B molecule.
The order of reaction is not related to the stoichiometric equation of reaction.
It means order of reaction is not equal to = a + b
It is an experimentally determined quantity.
Note: The reaction order is always defined in terms of the concentration of reactant and not of product.
Rate constant for first order depends only on time not concentration reactant.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

