
A doctor by mistake administers a $Ba{\left( {N{O_3}} \right)_2}$ solution to a patient for radiography investigations. Among these which of the following should be given as the best to prevent the absorption of soluble barium?
a.) $N{a_2}S{O_4}$
b.) $NaCl$
c.) $N{H_4}Cl$
d.) $N{a_2}C{O_3}$
Answer
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Hint: To solve this question we should first know about alkaline earth metals and periodic 6, s-block, and then we will learn about the absorption of soluble barium and its properties related to this question.
Complete step-by-step answer:
Barium: Barium is a chemical element, $Ba$ and having atomic no. 56.
It is the ${5^{th}}$ element in group 2 and is a soft, silvery alkaline earth metal. Due to its high chemical reactivity, it is never found in nature as a free element. It is not found in nature freely due to its high chemical reactivity.
Barium is also used in various industrial applications like, in vacuum tubes and in oxide form as the emissive coating on indirectly heated cathodes.
It imparts green color when added to firecrackers.
Barium sulfate is used as an (insoluble) additive to oil well drilling fluid, as well as in a purer form, as X-ray radiocontrast agent for imaging the human gastrointestinal tract.
The soluble barium ion and soluble compounds are poisonous in nature, and have been used as rodenticides.
Barium is insoluble in alcohol, soluble in concentrated hot sulfuric acid $\left( {N{a_2}S{O_4}} \right)$.
Hence, $N{a_2}S{O_4}$ should be given as the best to prevent the absorption of soluble barium. On reacting with the $B{a^{2 + }}$, the $N{a_2}S{O_4}$ gives $BaS{O_4}$ which precipitates.
$ \Rightarrow \,\,Ba{\left( {N{O_3}} \right)_2} + N{a_2}S{O_4} \to BaS{O_4}\left( {ppt} \right) + 2Na{\left( {N{O_3}} \right)_2}$
$BaS{O_4}$ (ppt) is the inorganic compound having chemical formula $BaS{O_4}$ .
Hence, the correct option is A. $N{a_2}S{O_4}$ .
NOTE - The reaction that has taken place is a good example of a double displacement reaction in which ion exchange takes place and thus Barium sulphate is formed as precipitate with Sodium nitrate. $BaS{O_4}$ is a crystalline white solid that is odourless and insoluble in water.
Complete step-by-step answer:
Barium: Barium is a chemical element, $Ba$ and having atomic no. 56.
It is the ${5^{th}}$ element in group 2 and is a soft, silvery alkaline earth metal. Due to its high chemical reactivity, it is never found in nature as a free element. It is not found in nature freely due to its high chemical reactivity.
Barium is also used in various industrial applications like, in vacuum tubes and in oxide form as the emissive coating on indirectly heated cathodes.
It imparts green color when added to firecrackers.
Barium sulfate is used as an (insoluble) additive to oil well drilling fluid, as well as in a purer form, as X-ray radiocontrast agent for imaging the human gastrointestinal tract.
The soluble barium ion and soluble compounds are poisonous in nature, and have been used as rodenticides.
Barium is insoluble in alcohol, soluble in concentrated hot sulfuric acid $\left( {N{a_2}S{O_4}} \right)$.
Hence, $N{a_2}S{O_4}$ should be given as the best to prevent the absorption of soluble barium. On reacting with the $B{a^{2 + }}$, the $N{a_2}S{O_4}$ gives $BaS{O_4}$ which precipitates.
$ \Rightarrow \,\,Ba{\left( {N{O_3}} \right)_2} + N{a_2}S{O_4} \to BaS{O_4}\left( {ppt} \right) + 2Na{\left( {N{O_3}} \right)_2}$
$BaS{O_4}$ (ppt) is the inorganic compound having chemical formula $BaS{O_4}$ .
Hence, the correct option is A. $N{a_2}S{O_4}$ .
NOTE - The reaction that has taken place is a good example of a double displacement reaction in which ion exchange takes place and thus Barium sulphate is formed as precipitate with Sodium nitrate. $BaS{O_4}$ is a crystalline white solid that is odourless and insoluble in water.
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