Question

A die is tossed $ 80 $ times and the number $ 3 $ is obtained $ 14 $ times. Now, a dice is tossed at random, then the probability of getting the number $ 3 $ is:
A. $ \dfrac{7}{{40}} $
B. $ \dfrac{3}{{14}} $
C. $ \dfrac{1}{2} $
D. $ \dfrac{3}{{40}} $

Answer 1

Hint: The definition of the probability is the number of favorable outcomes to the number of total outcomes. Use the given number of total outcomes and favorable outcomes to find the probability of getting the number $ 3 $ .

Complete step-by-step answer:
A die is tossed $ 80 $ times and the number $ 3 $ is obtained $ 14 $ times.
As it is given in the question, a die is tossed $ 80 $ times. So, the number of total outcomes is equal to $ 80 $ .
It is also given in the question that out of $ 80 $ times $ 3 $ appear $ 14 $ times. So, the number of favorable outcomes for getting $ 3 $ is equal to $ 14 $ .
The probability of an event is equal to the number of favorable outcomes to the number of total outcomes.
So, the probability of getting $ 3 $ on the die is equal to
 $ \dfrac{{14}}{{80}} = \dfrac{7}{{40}} $ .
So, the probability of getting $ 3 $ on the die is equal to $ \dfrac{7}{{40}} $ .
So, the correct answer is “Option A”.

Note: The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates impossibility of the event and 1 indicates certainty or sure event.
And the sum of probabilities of all the possible events irrespective of their individual value is always one.