A cord is used to lower vertically a block of mass M, through a distance d at a constant downward acceleration of $\dfrac{g}{8}$. Then the work done by the cord on the block is-
A. $\dfrac{{Mgd}}{8}$
B. $\dfrac{{3Mgd}}{8}$
C. $Mgd$
D. $\dfrac{{ - 7Mgd}}{8}$
Answer
627k+ views
Hint- The block is hanging from a cord so the tension will be in the upwards direction along the cord. The force acting on it due to gravity will be mg and the downward acceleration is given in the question as g/8. So, the net force will be the difference between the gravitational force and the Tension. Refer to the solution below.
Complete step-by-step answer:
Formula used: $F = ma$, ${W_{CB}} = \vec F.\vec d$
Since the tension is being applied on the block in the upwards direction and the gravitational force on the block is in the downward direction, the net force will be-
$ \Rightarrow {F_{net}} = Mg - T$
Now, according to the Newton’s second law of Motion, we can say that-
$ \Rightarrow F = ma$
$ \Rightarrow F = Ma$ (mass of the block is M)
Where m stands for mass of the body and a stand for the acceleration.
Equation the above formulas, we get-
$
\Rightarrow Mg - T = Ma \\
\\
\Rightarrow T = Mg - Ma \\
$
Substituting the value of acceleration i.e. g/8 as per given in the question in the above equation-
$
\Rightarrow T = Mg - M\dfrac{g}{8} \\
\\
\Rightarrow T = \dfrac{{7Mg}}{8} \\
$
Work done by the cord on the block-
$ \Rightarrow {W_{CB}} = \vec F.\vec d$ (dot product)
In this case, force applied is in the upwards direction which is Tension. Since the tension in working in the upwards direction and the displacement is in the downwards direction, the angle between these two forces will be 180 degrees. So-
$ \Rightarrow {W_{CB}} = \left| {\vec T} \right|\left| {\vec d} \right|\cos 180^\circ $
Substituting the values of tension in the above formula, we get-
$ \Rightarrow {W_{CB}} = \dfrac{{7Mg}}{8}d\left( { - 1} \right)$ ($\cos 180^\circ = - 1$)
$ \Rightarrow {W_{CB}} = - \dfrac{{7Mgd}}{8}$
Hence, option D is the correct option.
Note: Newton's second motion law is closely related to Newton's first motion law. This mathematically states the relation of cause and effect between force and motion changes. Newton's second law of motion is more abstract, and it is commonly used to measure what happens in circumstances involving a force.
Complete step-by-step answer:
Formula used: $F = ma$, ${W_{CB}} = \vec F.\vec d$
Since the tension is being applied on the block in the upwards direction and the gravitational force on the block is in the downward direction, the net force will be-
$ \Rightarrow {F_{net}} = Mg - T$
Now, according to the Newton’s second law of Motion, we can say that-
$ \Rightarrow F = ma$
$ \Rightarrow F = Ma$ (mass of the block is M)
Where m stands for mass of the body and a stand for the acceleration.
Equation the above formulas, we get-
$
\Rightarrow Mg - T = Ma \\
\\
\Rightarrow T = Mg - Ma \\
$
Substituting the value of acceleration i.e. g/8 as per given in the question in the above equation-
$
\Rightarrow T = Mg - M\dfrac{g}{8} \\
\\
\Rightarrow T = \dfrac{{7Mg}}{8} \\
$
Work done by the cord on the block-
$ \Rightarrow {W_{CB}} = \vec F.\vec d$ (dot product)
In this case, force applied is in the upwards direction which is Tension. Since the tension in working in the upwards direction and the displacement is in the downwards direction, the angle between these two forces will be 180 degrees. So-
$ \Rightarrow {W_{CB}} = \left| {\vec T} \right|\left| {\vec d} \right|\cos 180^\circ $
Substituting the values of tension in the above formula, we get-
$ \Rightarrow {W_{CB}} = \dfrac{{7Mg}}{8}d\left( { - 1} \right)$ ($\cos 180^\circ = - 1$)
$ \Rightarrow {W_{CB}} = - \dfrac{{7Mgd}}{8}$
Hence, option D is the correct option.
Note: Newton's second motion law is closely related to Newton's first motion law. This mathematically states the relation of cause and effect between force and motion changes. Newton's second law of motion is more abstract, and it is commonly used to measure what happens in circumstances involving a force.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

