
A copper cube \[0.30m\]on a side is subjected to a shearing force of \[F = 6.0 \times {10^6}N\]. Assuming that the shear modulus for copper is \[4.0 \times {10^{10}}N\]/$m^2$. The angle through which the cube shear is (approximately)
(a)$0.09$
(b)$0.21$
(c)\[0.15\]
(d)\[0.09\]
Answer
579k+ views
Hint:In order to solve this question, we need to use the formula for shear modulus.
Complete answer:
Shear modulus is calculated by as follows,
\[Shear{\text{ }}modulus = Shearing{\text{ }}stress/shearing{\text{ }}strain\]
Shearing$ = \dfrac{F}{A} = \dfrac{F}{{{a^2}}}$
Shearing strain$ = \tan \theta $
Shearing modulus\[ = \dfrac{{Shearing{\text{ }}stress}}{{shearing{\text{ }}strain}}\]
\[ \Rightarrow 4 \times {10^{10}} = \dfrac{{6 \times {{10}^6}}}{{\dfrac{{{{\left( {0.3} \right)}^2}}}{{\tan \theta }}}}\]
$ \Rightarrow \tan \theta = \dfrac{{6 \times {{10}^6}}}{{4 \times {{10}^{10}} \times 9 \times {{10}^{ - 2}}}}$
$ \Rightarrow \theta = ta{n^{ - 1}}\left( {\dfrac{{1 \times {{10}^{ - 2}}}}{6}} \right) = 0.095$
Hence, the correct answer to the question is option (a).
Additional Information:A lateral deformation is observed in the object when a shear force is applied to it. The elastic coefficient is known as shear modulus of rigidity. Shear modulus rigidity is the measurement of the rigidity of the object and it is obtained by measuring the ratio of shear stress of the object to the shear strain of the object.In materials science, shear modulus or modulus of rigidity, denoted by G, or sometimes S or μ, is defined as the ratio of shear stress to the shear strain: where = shear stress is the force which acts is the area on which the force acts = shear strain.
Note:While solving this question, we should be aware of the different types of formula used here. Especially shear modulus and how the different values of the variable of the formula is used from the question. The shear modulus formula is modified and used here to take out the required solution for the problem given here. Different formulae of shearing force is used here which must be taken into consideration while solving the question.
Complete answer:
Shear modulus is calculated by as follows,
\[Shear{\text{ }}modulus = Shearing{\text{ }}stress/shearing{\text{ }}strain\]
Shearing$ = \dfrac{F}{A} = \dfrac{F}{{{a^2}}}$
Shearing strain$ = \tan \theta $
Shearing modulus\[ = \dfrac{{Shearing{\text{ }}stress}}{{shearing{\text{ }}strain}}\]
\[ \Rightarrow 4 \times {10^{10}} = \dfrac{{6 \times {{10}^6}}}{{\dfrac{{{{\left( {0.3} \right)}^2}}}{{\tan \theta }}}}\]
$ \Rightarrow \tan \theta = \dfrac{{6 \times {{10}^6}}}{{4 \times {{10}^{10}} \times 9 \times {{10}^{ - 2}}}}$
$ \Rightarrow \theta = ta{n^{ - 1}}\left( {\dfrac{{1 \times {{10}^{ - 2}}}}{6}} \right) = 0.095$
Hence, the correct answer to the question is option (a).
Additional Information:A lateral deformation is observed in the object when a shear force is applied to it. The elastic coefficient is known as shear modulus of rigidity. Shear modulus rigidity is the measurement of the rigidity of the object and it is obtained by measuring the ratio of shear stress of the object to the shear strain of the object.In materials science, shear modulus or modulus of rigidity, denoted by G, or sometimes S or μ, is defined as the ratio of shear stress to the shear strain: where = shear stress is the force which acts is the area on which the force acts = shear strain.
Note:While solving this question, we should be aware of the different types of formula used here. Especially shear modulus and how the different values of the variable of the formula is used from the question. The shear modulus formula is modified and used here to take out the required solution for the problem given here. Different formulae of shearing force is used here which must be taken into consideration while solving the question.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

