A compound $ X $ of boron reacts with $ N{H_3} $ on heating to give another compound $ Y $ which is called inorganic benzene. The compound $ X $ can be prepared by treating $ B{F_3} $ with lithium aluminium hydride. The compound $ X $ and $ Y $ are represented by formula:
(A) $ {B_2}{H_6},{B_3}{N_3}{H_6} $
(B) $ {B_2}{O_3},{B_3}{N_3}{H_6} $
(C) $ B{F_3},{B_3}{N_3}{H_6} $
(D) $ {B_3}{N_3}{H_6},{B_2}{H_6} $
Answer
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Hint: Lithium aluminium hydride is a strong reducing agent having formula $ LiAl{H_4} $ and also known as LAH. Lithium aluminium hydride as having a strong reducing agent can reduce almost all the ketones into alcohol.
Complete step-by-step answer
First we start with the reaction,
$ X + N{H_3} \to Y $
Now, we have to know what inorganic benzene is.
Inorganic benzene: Inorganic benzene is an inorganic compound also known as Borazine having formula $ {B_3}{N_3}{H_6} $ .
As given is a compound of boron and is inorganic benzene.
Now, we have to know any reaction in which the formation of borazine with ammonia,
So, the reaction which forms borazine with ammonia,
$ 3{B_2}{H_6} + 6N{H_3} \to 2{B_3}{N_3}{H_6} $
So, the $ X $ is $ {B_2}{H_6} $ and the $ Y $ is $ {B_3}{N_3}{H_6} $ .
Also for confirmation the $ X $ is correct or not, we can use another given reaction.
We have to know the reaction of $ B{F_3} $ with lithium aluminium hydride,
So, the reaction of $ B{F_3} $ with lithium aluminium hydride as follows:
$ 4B{F_3} + LiAl{H_4} \to 2{B_2}{H_6} + 3LiF + 3Al{F_3} $
So, in these reaction only one compound of the boron that is $ {B_2}{H_6} $
So, from here we confirm that the $ X $ is $ {B_2}{H_6} $ also known as Diborane.
Hence, $ X $ is $ {B_2}{H_6} $ which is diborane and the $ Y $ is $ {B_3}{N_3}{H_6} $ which is borazine (Inorganic Benzene).
Hence, the correct option is (A) $ {B_2}{H_6},{B_3}{N_3}{H_6} $.
Additional information:
Diborane is having two types of bonds, one is covalent bond and another one is three-centre two electron bond and it is also a Lewis acid. It is most commonly used for the reduction of carboxylic acids.
Note:
Inorganic benzene is also known as Borazine or borazole which is having a formula $ {B_3}{N_3}{H_6} $ . It is a cyclic compound. The compound has the same structure and isoelectric with the benzene and having an inorganic compound named as inorganic benzene. Also, the borazine is more reactive than benzene.
Complete step-by-step answer
First we start with the reaction,
$ X + N{H_3} \to Y $
Now, we have to know what inorganic benzene is.
Inorganic benzene: Inorganic benzene is an inorganic compound also known as Borazine having formula $ {B_3}{N_3}{H_6} $ .
As given is a compound of boron and is inorganic benzene.
Now, we have to know any reaction in which the formation of borazine with ammonia,
So, the reaction which forms borazine with ammonia,
$ 3{B_2}{H_6} + 6N{H_3} \to 2{B_3}{N_3}{H_6} $
So, the $ X $ is $ {B_2}{H_6} $ and the $ Y $ is $ {B_3}{N_3}{H_6} $ .
Also for confirmation the $ X $ is correct or not, we can use another given reaction.
We have to know the reaction of $ B{F_3} $ with lithium aluminium hydride,
So, the reaction of $ B{F_3} $ with lithium aluminium hydride as follows:
$ 4B{F_3} + LiAl{H_4} \to 2{B_2}{H_6} + 3LiF + 3Al{F_3} $
So, in these reaction only one compound of the boron that is $ {B_2}{H_6} $
So, from here we confirm that the $ X $ is $ {B_2}{H_6} $ also known as Diborane.
Hence, $ X $ is $ {B_2}{H_6} $ which is diborane and the $ Y $ is $ {B_3}{N_3}{H_6} $ which is borazine (Inorganic Benzene).
Hence, the correct option is (A) $ {B_2}{H_6},{B_3}{N_3}{H_6} $.
Additional information:
Diborane is having two types of bonds, one is covalent bond and another one is three-centre two electron bond and it is also a Lewis acid. It is most commonly used for the reduction of carboxylic acids.
Note:
Inorganic benzene is also known as Borazine or borazole which is having a formula $ {B_3}{N_3}{H_6} $ . It is a cyclic compound. The compound has the same structure and isoelectric with the benzene and having an inorganic compound named as inorganic benzene. Also, the borazine is more reactive than benzene.
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