A circular coil of $ 100 $ turns and an effective diameter of $ 20cm $ carries a current of $ 0.5A $ . It is to be turned in a magnetic field $ 2.0\;T $ from a position in which the normal to the plane of the coil makes an angle $ \theta $ equal to zero to one in which $ \theta $ equals $ 180 $ . The work required in this process is:
(A) $ \pi J $
(B) $ 2\pi J $
(C) $ 4\pi J $
(D) $ 8\pi J $
Answer
555k+ views
Hint: We know the current is produced due to the flow of electrons. A current-carrying wire produces a magnetic field. Also, when a current-carrying wire is placed in a magnetic field it experiences a magnetic force. The direction of force is found by Fleming’s right-hand rule.
Complete answer:
Work done is stored as the potential energy of the system. So, we have the following formula.
$ W = U = - \vec m.\vec B $
Here, $ U $ is potential energy, $ m $ is magnetic dipole and $ B $ is a magnetic field.
Again, the magnetic dipole is calculated as below.
$ \vec m = IA\overset{\lower0.5em\hbox{ $ \smash{\scriptscriptstyle\frown} $ }}{n} $
Here, $ I $ is current, $ A $ is an area, and $ \hat n $ is the unit normal.
Let us first write the information given in the question.
$ N = 100 $ , $ d = 20cm \Rightarrow r = 10cm $ , $ I = 0.5A $ , $ B = 2T $ , $ {\theta _1} = 0 $ , $ {\theta _2} = 180 $
Magnetic moment: $ m = \left( {0.5} \right)\left( {\pi {{\left( {.10} \right)}^2}} \right) = 0.005\pi $
Work done will be a change in the potential energies.
$ W = mB\cos {\theta _1} - mB\cos {\theta _2} $
We can rewrite this expression as below.
$ W = mB\left( {\cos {\theta _1} - \cos {\theta _2}} \right) $
Let us substitute the values.
$ W = 0.005\pi \times 2\left( {\cos 0 - \cos 180} \right) $
Let us simplify the above expression.
$ W = 0.01\pi \left( {1 - \left( { - 1} \right)} \right) = 0.02\pi J $
Now, it is given that there are $ 100 $ turns. So total work done will become.
$ W = 100 \times 0.02\pi = 2\pi J $
Therefore, total work done is $ 2\pi J $ .
Hence, option (B) $ 2\pi J $ is correct.
Note:
The magnetic dipole moment of an object is defined as the torque experienced by the object in a magnetic field. Unit of a magnetic dipole is $ A - {m^2} $ .
Complete answer:
Work done is stored as the potential energy of the system. So, we have the following formula.
$ W = U = - \vec m.\vec B $
Here, $ U $ is potential energy, $ m $ is magnetic dipole and $ B $ is a magnetic field.
Again, the magnetic dipole is calculated as below.
$ \vec m = IA\overset{\lower0.5em\hbox{ $ \smash{\scriptscriptstyle\frown} $ }}{n} $
Here, $ I $ is current, $ A $ is an area, and $ \hat n $ is the unit normal.
Let us first write the information given in the question.
$ N = 100 $ , $ d = 20cm \Rightarrow r = 10cm $ , $ I = 0.5A $ , $ B = 2T $ , $ {\theta _1} = 0 $ , $ {\theta _2} = 180 $
Magnetic moment: $ m = \left( {0.5} \right)\left( {\pi {{\left( {.10} \right)}^2}} \right) = 0.005\pi $
Work done will be a change in the potential energies.
$ W = mB\cos {\theta _1} - mB\cos {\theta _2} $
We can rewrite this expression as below.
$ W = mB\left( {\cos {\theta _1} - \cos {\theta _2}} \right) $
Let us substitute the values.
$ W = 0.005\pi \times 2\left( {\cos 0 - \cos 180} \right) $
Let us simplify the above expression.
$ W = 0.01\pi \left( {1 - \left( { - 1} \right)} \right) = 0.02\pi J $
Now, it is given that there are $ 100 $ turns. So total work done will become.
$ W = 100 \times 0.02\pi = 2\pi J $
Therefore, total work done is $ 2\pi J $ .
Hence, option (B) $ 2\pi J $ is correct.
Note:
The magnetic dipole moment of an object is defined as the torque experienced by the object in a magnetic field. Unit of a magnetic dipole is $ A - {m^2} $ .
Recently Updated Pages
Which of the following graphs shows the variation of class 12 physics CBSE

Draw a labelled diagram of the human male reproductive class 12 biology CBSE

Describe the experiment to compare the emf of two cells class 12 physics CBSE

What is standard hydrogen electrode

What is conventional current and electric current class 12 physics CBSE

2Bromopentane is treated with an alcoholic KOH solution class 12 chemistry CBSE

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

A member of Simon commission later became Prime Minister class 12 social science CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

