
A certain fork is found to give \[3\,beats/s\] when sounded in conjunction with a stretched wire vibrating under a tension of either $4.32kg - wt$ or $3kg - wt$ . The frequency of fork is
A. $39\,Hz$
B. $30\,Hz$
C. $33\,Hz$
D. $36\,Hz$
Answer
512.7k+ views
Hint:A tuning fork is said to be an acoustic resonator which consists of a two pronged fork which is in the form of a U-shaped bar of elastic metal which is usually made up of steel. Pitch is responsible for the vibration. The pitch of the tuning fork depends on the tension, length and mass. The pitch is one of the characteristics of the sound which depends on the frequency.
Formula used:
Frequency of tuning fork is given by,
$f = \dfrac{1}{{2l}}\sqrt {\dfrac{T}{m}} $ ……….$\left( 1 \right)$
Where, $l = $ Length, $T = $ Tension and $m = $ Mass.
From equation frequency is related to tension as,
$f = \sqrt T $
Complete step by step answer:
We know that, frequency = $\sqrt {Tension} $
Therefore, ${f_1} = \sqrt {{T_1}} $ and ${f_2} = \sqrt {{T_2}} $
Given, ${T_1} = 4.32$ and ${T_2} = 3$
${f_1} - {f_0} = 3$
Therefore, ${f_1} = {f_0} + 3$ ………. $\left( 1 \right)$
${f_0} - {f_2} = 3$
Therefore, ${f_2} = {f_0} - 3$ ……… $\left( 2 \right)$
Hence, it can be written as
$\dfrac{{{f_1}}}{{{f_2}}} = \sqrt {\dfrac{{{T_1}}}{{{T_2}}}} $
Substituting the values of ${T_1}$ and ${T_2}$ in the above equation we get
$\dfrac{{{f_1}}}{{{f_2}}} = \sqrt {\dfrac{{4.32}}{3}} $ ………… $\left( 3 \right)$
Substituting equation $\left( 1 \right)$ and equation $\left( 2 \right)$ in equation $\left( 3 \right)$ we get
$\dfrac{{{f_0} + 3}}{{{f_0} - 3}} = \sqrt {\dfrac{{4.32}}{3}} $
On simplifying, we get
$\left( {\dfrac{{{f_0} + 3}}{{{f_0} - 3}}} \right) = 1.2$
$\Rightarrow {f_0} + 3 = 1.2\left( {{f_0} - 3} \right)$
On further simplification
${f_0} + 3 = 1.2{f_0} - 3.6$
\[\Rightarrow {f_0} - 1.2{f_0} = - 3.6 - 3\]
\[\Rightarrow - 0.2{f_0} = - 6.6\]
\[\Rightarrow {f_0} = \dfrac{{ - 6.6}}{{ - 0.2}}\]
$\therefore {f_0} = 33\,Hz$
Hence, option C is correct.
Note:The frequency of the tuning fork and the frequency of the string will be the same if the string and the tuning fork vibrate at resonance. The tension in the string is defined as the pulling force that is transmitted axially by means of a string. The sound depends on the characteristics that are loudness which depends on the amplitude, quality which depends on the nature of waveform and pitch which depends on the frequency.
Formula used:
Frequency of tuning fork is given by,
$f = \dfrac{1}{{2l}}\sqrt {\dfrac{T}{m}} $ ……….$\left( 1 \right)$
Where, $l = $ Length, $T = $ Tension and $m = $ Mass.
From equation frequency is related to tension as,
$f = \sqrt T $
Complete step by step answer:
We know that, frequency = $\sqrt {Tension} $
Therefore, ${f_1} = \sqrt {{T_1}} $ and ${f_2} = \sqrt {{T_2}} $
Given, ${T_1} = 4.32$ and ${T_2} = 3$
${f_1} - {f_0} = 3$
Therefore, ${f_1} = {f_0} + 3$ ………. $\left( 1 \right)$
${f_0} - {f_2} = 3$
Therefore, ${f_2} = {f_0} - 3$ ……… $\left( 2 \right)$
Hence, it can be written as
$\dfrac{{{f_1}}}{{{f_2}}} = \sqrt {\dfrac{{{T_1}}}{{{T_2}}}} $
Substituting the values of ${T_1}$ and ${T_2}$ in the above equation we get
$\dfrac{{{f_1}}}{{{f_2}}} = \sqrt {\dfrac{{4.32}}{3}} $ ………… $\left( 3 \right)$
Substituting equation $\left( 1 \right)$ and equation $\left( 2 \right)$ in equation $\left( 3 \right)$ we get
$\dfrac{{{f_0} + 3}}{{{f_0} - 3}} = \sqrt {\dfrac{{4.32}}{3}} $
On simplifying, we get
$\left( {\dfrac{{{f_0} + 3}}{{{f_0} - 3}}} \right) = 1.2$
$\Rightarrow {f_0} + 3 = 1.2\left( {{f_0} - 3} \right)$
On further simplification
${f_0} + 3 = 1.2{f_0} - 3.6$
\[\Rightarrow {f_0} - 1.2{f_0} = - 3.6 - 3\]
\[\Rightarrow - 0.2{f_0} = - 6.6\]
\[\Rightarrow {f_0} = \dfrac{{ - 6.6}}{{ - 0.2}}\]
$\therefore {f_0} = 33\,Hz$
Hence, option C is correct.
Note:The frequency of the tuning fork and the frequency of the string will be the same if the string and the tuning fork vibrate at resonance. The tension in the string is defined as the pulling force that is transmitted axially by means of a string. The sound depends on the characteristics that are loudness which depends on the amplitude, quality which depends on the nature of waveform and pitch which depends on the frequency.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

