A Carnot engine takes 100 calories of heat from a reservoir at \[{427^0}C\]and performs 60 Kcal of work. Calculate the amount of heat absorbed in joule.
A. 10 J
B. 20 J
C. 68 J
D. None of the above
Answer
604.5k+ views
Hint: In this question, we need to determine the amount of heat absorbed by the Carnot engine for the useful work of 600 Kcal to be done such that it takes 100 calories of heat from the reservoir. For this, we will use the relation between the heat exchange from the Carnot engine and the work is done, which is given as $W = {Q_1} - {Q_2}$.
Complete step by step answer:The difference in the heat exchange from the reservoir in the Carnot engine results in the work done by the Carnot engine. Mathematically, $W = {Q_1} - {Q_2}$ where, $W$ is the work done by the Carnot engine, ${Q_1}$ is the heat taken by the Carnot engine from the reservoir and ${Q_2}$ is the heat absorbed by the Carnot engine. Here, $W = 60Kcal{\text{ and }}{Q_1} = 100cal$.
So, substitute $W = 60Kcal{\text{ and }}{Q_1} = 100cal$ in the formula $W = {Q_1} - {Q_2}$ to determine the heat absorbed by the Carnot engine in calories.
$
W = {Q_1} - {Q_2} \\
60Kcal = 100Cal - {Q_2} \\
{Q_2} = 100cal - 60Kcal \\
{Q_2} = 100cal - 60000cal \\
{Q_2} = - 59900cal - - - - (i) \\
$
Now, one calorie of heat is equivalent to 4.184 joules, i.e., $1cal = 4.184joules$
Hence, the result in equation (i) can be converted into joules as.
$
- 59900cal = - 59900 \times 4.184joules \\
= - 250621.6joules \\
$
Hence, the amount of heat absorbed by the Carnot engine from the reservoir is -250621.6 Joules, which is also equivalent to -250.62 Kjoules. Hence, none of the given options are correct.
Option D is correct.
Note:Students must be careful while using the formula $W = {Q_1} - {Q_2}$ sign convention plays an important role here. ${Q_1}$ is the heat taken by the Carnot engine from the reservoir (which should always be positive with respect to the reservoir) and ${Q_2}$ is the heat absorbed by the Carnot engine (which should always be negative with respect to the reservoir).
Complete step by step answer:The difference in the heat exchange from the reservoir in the Carnot engine results in the work done by the Carnot engine. Mathematically, $W = {Q_1} - {Q_2}$ where, $W$ is the work done by the Carnot engine, ${Q_1}$ is the heat taken by the Carnot engine from the reservoir and ${Q_2}$ is the heat absorbed by the Carnot engine. Here, $W = 60Kcal{\text{ and }}{Q_1} = 100cal$.
So, substitute $W = 60Kcal{\text{ and }}{Q_1} = 100cal$ in the formula $W = {Q_1} - {Q_2}$ to determine the heat absorbed by the Carnot engine in calories.
$
W = {Q_1} - {Q_2} \\
60Kcal = 100Cal - {Q_2} \\
{Q_2} = 100cal - 60Kcal \\
{Q_2} = 100cal - 60000cal \\
{Q_2} = - 59900cal - - - - (i) \\
$
Now, one calorie of heat is equivalent to 4.184 joules, i.e., $1cal = 4.184joules$
Hence, the result in equation (i) can be converted into joules as.
$
- 59900cal = - 59900 \times 4.184joules \\
= - 250621.6joules \\
$
Hence, the amount of heat absorbed by the Carnot engine from the reservoir is -250621.6 Joules, which is also equivalent to -250.62 Kjoules. Hence, none of the given options are correct.
Option D is correct.
Note:Students must be careful while using the formula $W = {Q_1} - {Q_2}$ sign convention plays an important role here. ${Q_1}$ is the heat taken by the Carnot engine from the reservoir (which should always be positive with respect to the reservoir) and ${Q_2}$ is the heat absorbed by the Carnot engine (which should always be negative with respect to the reservoir).
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

