Question

A car travels a distance of $258km$ in $3$ hours $35$ minutes. What is the speed of the car?

Answer 1

Hint: First, the given problem is based on the quantity of speed, distance, and time. The relation between them can be expressed as $S = \dfrac{D}{T}$ where S is the speed, T is the time taken and D is the distance covered.
We will convert the given minutes into hours by dividing them by $60$. Which are hours to minutes conversion.

Complete step by step answer:
Given that A car travels a distance of $258km$ in $3$ hours $35$ minutes and then we have to find the speed of the car.
Let us fix the speed of the car as S, to find the speed convert the given time in one quantity, that is hours.
Thus the $3$ hours and $35$ minutes can be rewritten as $3 + \dfrac{{35}}{{60}}$ hours.
Canceling the common terms, we get $3 + \dfrac{7}{{12}} = \dfrac{{43}}{{12}}$ hours.
Now we use the formula that $S = \dfrac{D}{T}$ where distance is $258km$ and time is $\dfrac{{43}}{{12}}$ hours.
Then we get $S = \dfrac{D}{T} $
$\Rightarrow \dfrac{{258}}{{\dfrac{{43}}{{12}}}} = \dfrac{{258 \times 12}}{{43}}$
By the division operation, we get $S = 6 \times 12$
By the multiplication we get $S = 72$
Hence the speed of the car is $72km/hr$

Note:
The operations which we used to solve the problem are multiplication and division operations.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to a number that multiplies the first number. Have a look at an example; while multiplying $5 \times 7$ the number $5$ is called the multiplicand and the number $7$ is called the multiplier. Like $S = 6 \times 12$, $S = 72$
The process of the inverse of the multiplication method is called division. Like $x \times y = z$ is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $\dfrac{{258}}{{43}} = 6$