Question

A car travels a distance of $ 200km $ from Delhi to Ambala towards North in $ 5 $ hours. Calculate (i) speed, and (ii) velocity, of the car for this journey.

Answer 1

Hint: First we have to define what the terms we need to solve the problem are.
Distance is a numerical measurement; Velocity is equivalent to a specification of an object's speed and direction of motion. Time refers to the duration in hours, minutes, or seconds spent to cover a particular distance.

Complete step by step answer:
From the given question a car travels a distance of $ 200km $ from Delhi to Ambala towards North in
 $ 5 $ hours. And first we need to calculate the speed of the car for this journey.
Speed is defined as the rate at which an object moves from one place to another in an interval of time. It is scalar as it defines only the magnitude not directions of an object. The S.I unit of speed is $ \dfrac{m}{s} $
The speed of a moving object can be calculated as $ speed = \dfrac{{Dis\tan ce}}{{time}} $
The distance travelled by car is $ 200km $ and time is $ 5 $ hours.
Hence substitute the known values on the formula we get $ speed = \dfrac{{200km}}{{5hr}} $
And thus, (i) the speed of the car is $ speed = 40km $ per hour.
Now we need to find the velocity of the car for this journey
That is $ velocity = \dfrac{{displacement}}{{time taken}} $ . Since Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude, thus displacement is also the distance given in this problem $ velocity = \dfrac{{displacement}}{{time taken}} \Rightarrow \dfrac{{200}}{5} $ towards north (direction)
And hence (ii) $ velocity = 40km $ per hour towards north.
Thus, we find the velocity and speed of the given problem.

Note: Distance is a numerical measurement; Velocity is equivalent to a specification of an object's speed and direction of motion Time refers to the duration in hours, minutes, or seconds spent to cover a particular distance. Time taken by moving objects to cover a certain distance is calculated as $time = \dfrac{{dis\tan ce}}{{speed}}$.