A car is moving on a straight road. The velocity of the car varies with time as shown in figure. Initially (at \[t=0\]), the car was at x=0, where, x is the position of the car at any time t. Average speed from \[t=0\]tot \[t=70s\]will be:
Answer
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Hint: The velocity time graph gives the displacement. When the slope of the velocity time graph will be above the x-axis, then, the displacement is considered to be positive. Similarly, when the slope of the velocity time graph will be below the x-axis, then, the displacement is considered to be negative.
Formula used:
\[\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}\]
Complete step-by-step solution:
From the given information, we have the data as follows.
The displacement is positive till the curve crosses the x-axis at 50 seconds, after this time, the displacement is negative, as the curve is below the x-axis. Thus, the positive displacements get added up, while the negative ones get subtracted.
The formula for computing the average speed is,
\[\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}\]
The maximum displacement equals the area under the curve till the time 50 seconds. This area equals the sum of the area of the triangle till the time 10 seconds and the area of the rectangle from time 10 seconds till 20 seconds and the area of the trapezium from the time 20 seconds till the time 30 seconds and the area of the triangle from the time 30 seconds till 50 seconds.
Substitute the values in the above formula
\[\text{Average speed}=\dfrac{{}^{1}/{}_{2}\times 10\times 4+20\times 4+{}^{1}/{}_{2}\times 10\times 4+{}^{1}/{}_{2}\times 20\times 8+{}^{1}/{}_{2}\times 20\times 4}{70}\]
Continue further computation.
\[\begin{align}
& \text{Average speed}=\dfrac{20+80+20+80+40}{70} \\
& \Rightarrow \text{Average speed}=\dfrac{240}{70} \\
& \therefore \text{Average speed}=3.42\,{m}/{s}\; \\
\end{align}\]
\[\therefore \] The average speed of a car moving on a straight road will be, \[3.42\,{m}/{s}\;\].
Note: There are different types of graph considering the parameters of the motion with respect to the time, such as, the displacement time graph, velocity time graph and the acceleration time graph. The slope of the displacement time graph gives the velocity, the slope of the velocity time graph gives the acceleration and slope of the acceleration time graph gives the change in the velocity.
Formula used:
\[\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}\]
Complete step-by-step solution:
From the given information, we have the data as follows.
The displacement is positive till the curve crosses the x-axis at 50 seconds, after this time, the displacement is negative, as the curve is below the x-axis. Thus, the positive displacements get added up, while the negative ones get subtracted.
The formula for computing the average speed is,
\[\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}\]
The maximum displacement equals the area under the curve till the time 50 seconds. This area equals the sum of the area of the triangle till the time 10 seconds and the area of the rectangle from time 10 seconds till 20 seconds and the area of the trapezium from the time 20 seconds till the time 30 seconds and the area of the triangle from the time 30 seconds till 50 seconds.
Substitute the values in the above formula
\[\text{Average speed}=\dfrac{{}^{1}/{}_{2}\times 10\times 4+20\times 4+{}^{1}/{}_{2}\times 10\times 4+{}^{1}/{}_{2}\times 20\times 8+{}^{1}/{}_{2}\times 20\times 4}{70}\]
Continue further computation.
\[\begin{align}
& \text{Average speed}=\dfrac{20+80+20+80+40}{70} \\
& \Rightarrow \text{Average speed}=\dfrac{240}{70} \\
& \therefore \text{Average speed}=3.42\,{m}/{s}\; \\
\end{align}\]
\[\therefore \] The average speed of a car moving on a straight road will be, \[3.42\,{m}/{s}\;\].
Note: There are different types of graph considering the parameters of the motion with respect to the time, such as, the displacement time graph, velocity time graph and the acceleration time graph. The slope of the displacement time graph gives the velocity, the slope of the velocity time graph gives the acceleration and slope of the acceleration time graph gives the change in the velocity.
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