A car increases its speed from 20 km/h to 40 km/h in 10 seconds. What is its acceleration?
Answer
640.2k+ views
Hint: In this question we have been asked to calculate the acceleration of a car. It is given that the speed of a car is increased from 20 km/h to 40 km/h in 10 seconds. We know that rate of change of velocity or speed is given as acceleration. We also know that the relation between the initial velocity, final velocity, time, and acceleration is given by the second kinematic equation. Therefore, we shall use this equation to calculate the acceleration of the given car.
Formula used:-
\[v=u+at\]
Where,
V is the final velocity
U is the initial velocity
T is the time and
A is the acceleration
Complete step-by-step solution
It is given that the speed of a car increases from 20 km/h to 40 km/h. therefore, we can say that,
\[v=40km/h\] , \[u=20km/h\]. Also, it is given that time \[t=10\sec \]
Now, the units of time and velocities are different. Therefore, after the conversion of units
We get,
\[v=11.11m/s\] and \[u=5.5m/s\] …………… (1)
Now, from the second kinematic equation
We knew,
\[v=u+at\]
After substituting the values from (1)
We get,
\[11.11=5.5+10a\]
On solving
We get,
\[a=0.56m/{{s}^{2}}\]
Therefore, the acceleration of the given car is 0.56 metre per second squared.
Note: Kinematic analysis the process of measuring the kinematic quantities such as velocity and acceleration used to describe the motion. There are five main kinematic equations. If a body is moving with a constant acceleration, the kinematic equations may be used to determine the initial speed, final speed, acceleration, or distance covered by the object in unit time. It is required that some of the kinematic quantities be known to determine the others.
Formula used:-
\[v=u+at\]
Where,
V is the final velocity
U is the initial velocity
T is the time and
A is the acceleration
Complete step-by-step solution
It is given that the speed of a car increases from 20 km/h to 40 km/h. therefore, we can say that,
\[v=40km/h\] , \[u=20km/h\]. Also, it is given that time \[t=10\sec \]
Now, the units of time and velocities are different. Therefore, after the conversion of units
We get,
\[v=11.11m/s\] and \[u=5.5m/s\] …………… (1)
Now, from the second kinematic equation
We knew,
\[v=u+at\]
After substituting the values from (1)
We get,
\[11.11=5.5+10a\]
On solving
We get,
\[a=0.56m/{{s}^{2}}\]
Therefore, the acceleration of the given car is 0.56 metre per second squared.
Note: Kinematic analysis the process of measuring the kinematic quantities such as velocity and acceleration used to describe the motion. There are five main kinematic equations. If a body is moving with a constant acceleration, the kinematic equations may be used to determine the initial speed, final speed, acceleration, or distance covered by the object in unit time. It is required that some of the kinematic quantities be known to determine the others.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

