
(a) Calculate the molarity of hydrogen chloride in a solution when $ 0.365{\text{ }}g $ of it has been dissolved in $ 100{\text{ }}mL $ of solution?
(b) $ 3.0{\text{ }}g $ of a salt of molecular weight $ 30 $ is dissolved in $ 250{\text{ }}ml $ water. The molality of solution is:
Answer
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Hint :Before going through the question let us first know about the key terms related to this question i.e. molarity and molality. The number of solvent moles present in $ 1{\text{ }}L $ of solution is defined as molarity. The volume of solutions comprises the denominator. The volume depends on the system temperature. The number of solute moles that are present in $ 1{\text{ }}kg $ of solvent is defined as molality. This unit is made up of mass conditions and is temperature independent.
Complete Step By Step Answer:
Now, let us solve the questions accordingly;
(a) The molarity of hydrogen chloride in a solution when $ 0.365{\text{ }}g $ of it has been dissolved in $ 100{\text{ }}mL $ of solution is:
Molarity $ \left( M \right) $ = $ \dfrac{n}{v} $
$ M = $ Molar concentration
$ n = $ Moles of solute
$ v = $ Litres of solution
No. of moles $ (n) = $ $ \dfrac{{mass}}{{molar\,mass}} $
For $ HCl $ ;
Mass = $ 0.365{\text{ }}g $
Molar mass = $ {\text{36}}{\text{.5 g/mol }} $
Volume = $ 100mL = 0.1{\text{ }}L $
Thus, molarity = $ \dfrac{{0.365}}{{36.5 \times 0.1}} = 0.1M $
Therefore, the molarity of hydrogen chloride is $ 0.1M $ .
(b) $ 3.0{\text{ }}g $ of a salt of molecular weight $ 30 $ is dissolved in $ 250{\text{ }}ml $ water. The molality of solution is
The term for solution molality is:
$ = \dfrac{{Number\,of\,moles\,of\,solute}}{{Weight\,of\,solvent\,in\,Kg}} \\
= \dfrac{{Weight\,of\,solute}}{{Molar\,mass}} \times \dfrac{{1000}}{{Weight\,of\,solvent\,in\,Kg}} \\
= \dfrac{3}{{30}} \times \dfrac{{1000}}{{250}} = 0.4M \\ $
Therefore, the molality of the solution is $ 0.4M $ .
Note :
Although molarity is usually used to express concentrations for solution reactions or for titrations, there is one drawback — molarity is the number of solute moles divided by solution volume, and the solution volume varies according to the density of the solution, depending on the temperature.
Complete Step By Step Answer:
Now, let us solve the questions accordingly;
(a) The molarity of hydrogen chloride in a solution when $ 0.365{\text{ }}g $ of it has been dissolved in $ 100{\text{ }}mL $ of solution is:
Molarity $ \left( M \right) $ = $ \dfrac{n}{v} $
$ M = $ Molar concentration
$ n = $ Moles of solute
$ v = $ Litres of solution
No. of moles $ (n) = $ $ \dfrac{{mass}}{{molar\,mass}} $
For $ HCl $ ;
Mass = $ 0.365{\text{ }}g $
Molar mass = $ {\text{36}}{\text{.5 g/mol }} $
Volume = $ 100mL = 0.1{\text{ }}L $
Thus, molarity = $ \dfrac{{0.365}}{{36.5 \times 0.1}} = 0.1M $
Therefore, the molarity of hydrogen chloride is $ 0.1M $ .
(b) $ 3.0{\text{ }}g $ of a salt of molecular weight $ 30 $ is dissolved in $ 250{\text{ }}ml $ water. The molality of solution is
The term for solution molality is:
$ = \dfrac{{Number\,of\,moles\,of\,solute}}{{Weight\,of\,solvent\,in\,Kg}} \\
= \dfrac{{Weight\,of\,solute}}{{Molar\,mass}} \times \dfrac{{1000}}{{Weight\,of\,solvent\,in\,Kg}} \\
= \dfrac{3}{{30}} \times \dfrac{{1000}}{{250}} = 0.4M \\ $
Therefore, the molality of the solution is $ 0.4M $ .
Note :
Although molarity is usually used to express concentrations for solution reactions or for titrations, there is one drawback — molarity is the number of solute moles divided by solution volume, and the solution volume varies according to the density of the solution, depending on the temperature.
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