
A bus appears to go with a speed of \[25{km}/{hr}\;\]to a car driver, driving at the rate \[7{km}/{hr}\;\] northwards. If the bus actually travels in the east direction, its speed is
\[A.\,24{km}/{hr}\;\]
\[B.\,23{km}/{hr}\;\]
\[C.\,26{km}/{hr}\;\]
\[D.\,30{km}/{hr}\;\]
Answer
554.7k+ views
Hint: This question is based on the concept of the directions. The resultant velocity is the solution of the answer along the north-east direction, as the car is moving along the north direction and the bus is considered to be moving along the east direction. The resultant velocity is the root of the sum of the squares of the velocities of the bus (according to the car driver) and car.
Formula used:
\[V_{R}^{2}=V_{x}^{2}+V_{y}^{2}\]
Complete answer:
The resultant velocity is given by the formula as follows.
\[V_{R}^{2}=V_{x}^{2}+V_{y}^{2}\]
Where \[{{V}_{x}}\] represents the vector along the x-axis direction and \[{{V}_{y}}\] represents the vector along the y-axis direction.
From the data, we have the data as follows.
To a car driver, the bus appeared to go with a speed of \[25{km}/{hr}\;\], but the direction is not mentioned. So, \[{{V}_{NE}}=25{km}/{hr}\;\]
The car driver is driving the car at the rate\[7{km}/{hr}\;\] northwards. So, \[{{V}_{N}}=7{km}/{hr}\;\]
The question is to find the speed of the bus, if considered, the direction of the bus is east.
So, we have,
The car is moving in the north direction and the bus is considered to be moving in the east direction, thus, the resultant velocity will be along the north-east direction. Thus, we have the formula as follows.
\[V_{NE}^{2}=V_{E}^{2}+V_{N}^{2}\]
Substitute the given values in the above equation.
\[\begin{align}
& {{25}^{2}}=V_{E}^{2}+{{7}^{2}} \\
& \Rightarrow V_{E}^{2}={{25}^{2}}-{{7}^{2}} \\
\end{align}\]
Continue the further calculation.
\[\begin{align}
& V_{E}^{2}=625-49 \\
& \Rightarrow {{V}_{E}}=24{km}/{hr}\; \\
\end{align}\]
\[\therefore \] The value of the speed of the bus, considering the actual direction of the bus to be along the east direction is \[24{km}/{hr}\;\] .
Thus, the option (A) is correct.
Note:
The question is a bit confusing while considering the directions. As the two of the three directions are given, so it is obvious that, the resultant velocity will have the direction in between the other two velocities in some cases and the resultant will be in between but tilted.
Formula used:
\[V_{R}^{2}=V_{x}^{2}+V_{y}^{2}\]
Complete answer:
The resultant velocity is given by the formula as follows.
\[V_{R}^{2}=V_{x}^{2}+V_{y}^{2}\]
Where \[{{V}_{x}}\] represents the vector along the x-axis direction and \[{{V}_{y}}\] represents the vector along the y-axis direction.
From the data, we have the data as follows.
To a car driver, the bus appeared to go with a speed of \[25{km}/{hr}\;\], but the direction is not mentioned. So, \[{{V}_{NE}}=25{km}/{hr}\;\]
The car driver is driving the car at the rate\[7{km}/{hr}\;\] northwards. So, \[{{V}_{N}}=7{km}/{hr}\;\]
The question is to find the speed of the bus, if considered, the direction of the bus is east.
So, we have,
The car is moving in the north direction and the bus is considered to be moving in the east direction, thus, the resultant velocity will be along the north-east direction. Thus, we have the formula as follows.
\[V_{NE}^{2}=V_{E}^{2}+V_{N}^{2}\]
Substitute the given values in the above equation.
\[\begin{align}
& {{25}^{2}}=V_{E}^{2}+{{7}^{2}} \\
& \Rightarrow V_{E}^{2}={{25}^{2}}-{{7}^{2}} \\
\end{align}\]
Continue the further calculation.
\[\begin{align}
& V_{E}^{2}=625-49 \\
& \Rightarrow {{V}_{E}}=24{km}/{hr}\; \\
\end{align}\]
\[\therefore \] The value of the speed of the bus, considering the actual direction of the bus to be along the east direction is \[24{km}/{hr}\;\] .
Thus, the option (A) is correct.
Note:
The question is a bit confusing while considering the directions. As the two of the three directions are given, so it is obvious that, the resultant velocity will have the direction in between the other two velocities in some cases and the resultant will be in between but tilted.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

