A bullet moving with velocity collides against a wall, consequently half of its kinetic energy is converted to heat. If the whole heat is acquired by the bullet then the rise in temperature will be:
Answer
577.8k+ views
Hint: Moving particles lose energy mostly through friction so that their kinetic energies eventually get transferred to heat energy.
First, one should know about the kinetic energy expression.
Then here is the question, it is mentioned that half of the kinetic energy will be converted to heat energy
Hence after writing the kinetic energy expression just do half of the energy that will be converted to heat.
After that use the formula for heat absorbed by a body in terms of specific heat and change in temperature and then finally equate that with the previously found heat energy absorbed by the bullet.
Formula used:
Kinetic energy = $0.5m{v^2}$
Heat absorbed = \[ms({t_2} - {t_1})\]
Complete step-by-step solution:
For a bullet with mass=\[m\] and velocity=\[v\] ;
the kinetic energy of bullet= = $0.5m{v^2}$
Half of the kinetic energy is converted to Heat energy
So, heat absorbed by bullet = $\dfrac{{0.5m{v^2}}}{2}$
Therefore, heat absorbed by bullet = $0.25m{v^2}$
Now, we will use the expression for heat absorbed in terms of specific heat and change in temperature
Heat absorbed = \[ms({t_2} - {t_1})\]; where s= specific heat and \[({t_2} - {t_1})\]= change in temperature
Accordingly now,
$0.25m{v^2} = ms({t_2} - {t_1})$
Therefore, from the above equation \[({t_2} - {t_1}) = \dfrac{{{v^2}}}{{4s}}\] is the temperature rise.
Hence option A is correct.
Note: When the bullet hits the target then both the bullet and the target get deformed and hence the Kinetic energy of the bullet gets converted to heat energy. When we heat a substance past its melting point, whatever energy we add to it, goes into melting another portion of the mass hence the concept of latent heat is useful in solving such problems. We can define the Heat capacity of a substance as the heat absorbed by the substance for change in temperature by one degree. Specific heat capacity is defined as heat absorbed per unit gram of a substance to result in a change of temperature by one degree.
First, one should know about the kinetic energy expression.
Then here is the question, it is mentioned that half of the kinetic energy will be converted to heat energy
Hence after writing the kinetic energy expression just do half of the energy that will be converted to heat.
After that use the formula for heat absorbed by a body in terms of specific heat and change in temperature and then finally equate that with the previously found heat energy absorbed by the bullet.
Formula used:
Kinetic energy = $0.5m{v^2}$
Heat absorbed = \[ms({t_2} - {t_1})\]
Complete step-by-step solution:
For a bullet with mass=\[m\] and velocity=\[v\] ;
the kinetic energy of bullet= = $0.5m{v^2}$
Half of the kinetic energy is converted to Heat energy
So, heat absorbed by bullet = $\dfrac{{0.5m{v^2}}}{2}$
Therefore, heat absorbed by bullet = $0.25m{v^2}$
Now, we will use the expression for heat absorbed in terms of specific heat and change in temperature
Heat absorbed = \[ms({t_2} - {t_1})\]; where s= specific heat and \[({t_2} - {t_1})\]= change in temperature
Accordingly now,
$0.25m{v^2} = ms({t_2} - {t_1})$
Therefore, from the above equation \[({t_2} - {t_1}) = \dfrac{{{v^2}}}{{4s}}\] is the temperature rise.
Hence option A is correct.
Note: When the bullet hits the target then both the bullet and the target get deformed and hence the Kinetic energy of the bullet gets converted to heat energy. When we heat a substance past its melting point, whatever energy we add to it, goes into melting another portion of the mass hence the concept of latent heat is useful in solving such problems. We can define the Heat capacity of a substance as the heat absorbed by the substance for change in temperature by one degree. Specific heat capacity is defined as heat absorbed per unit gram of a substance to result in a change of temperature by one degree.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

What is the maximum height of a projectile class 11 physics CBSE

Derive an expression for maximum height and range of class 11 physics CBSE

Describe various types of epithelial tissues with the class 11 biology CBSE

Lysosomes are known as suicidal bags of cell why class 11 biology CBSE

State and derive law of conservation of momentum class 11 physics CBSE

