A boy carries a fish in one hand and a bucket (not full) of water in the other hand. If he places the fish in the bucket, the weight now carried by him (assume that water does not spill)
A. is less than before
B. is more than before
C. is the same as before
D. depends upon his speed.
Answer
667.2k+ views
Hint: The above problem can be resolved by using the concepts of Buoyancy and fundamentals of the buoyant force. As the buoyant force has its significance in determining the apparent weight of the body being fully submerged as well as partially submerged. Moreover, Buoyancy has its vital applications in determining the metacentre of the body.
Complete step by step answer:
Given: The boy carrying the fish in one hand and a bucket of water in the other hand.
The boy holding the fish in one hand, while the bucket full of water on the other hand creates some system of forces to be acting between the water in the bucket and the fish. The water in the bucket applies some magnitude of buoyant force on the fish, that is exactly equivalent and is opposite to the force applied by the fish on water. Due to this, both forces cancel out their effect, resulting in no variation in the weight carried by the boy.
Therefore, the weight carried by the boy will remain same as before
So, the correct answer is “Option C”.
Note:
The problem involves determining the change in weight for the submerged body in water. This accounts for the involvement of fundamental concepts of Buoyant force as well as the phenomena known as Buoyancy. Moreover, the balancing of forces is also important to predict the apparent weight of the object being submerged underneath the water.
Complete step by step answer:
Given: The boy carrying the fish in one hand and a bucket of water in the other hand.
The boy holding the fish in one hand, while the bucket full of water on the other hand creates some system of forces to be acting between the water in the bucket and the fish. The water in the bucket applies some magnitude of buoyant force on the fish, that is exactly equivalent and is opposite to the force applied by the fish on water. Due to this, both forces cancel out their effect, resulting in no variation in the weight carried by the boy.
Therefore, the weight carried by the boy will remain same as before
So, the correct answer is “Option C”.
Note:
The problem involves determining the change in weight for the submerged body in water. This accounts for the involvement of fundamental concepts of Buoyant force as well as the phenomena known as Buoyancy. Moreover, the balancing of forces is also important to predict the apparent weight of the object being submerged underneath the water.
Recently Updated Pages
Which will be the least stable resonating structure class 11 chemistry CBSE

How many 5 digit telephone numbers can be construc-class-11-maths-CBSE

How do you find the angle of the resultant vector class 11 physics CBSE

Draw labelled diagram of the following i Gram seed class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is the need and importance of classification class 11 biology CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

10 examples of friction in our daily life

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference between physical and chemical change class 11 chemistry CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

