Question

A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively $1094$, $1812$, $2050$ and $2751$. Find the total number of tickets sold on all the four days.

Answer 1

Hint: The given problem revolves around the concepts of basic arithmetic and operations. In the given question, we are provided with the number of tickets sold on four consecutive days at the counter and we have to find the total number of tickets sold in four days. We break down the information given to us to try and identify what must be done in order to solve the problem. So, we have to compute the sum of these four numbers to get to the required answer.

Complete step by step answer:
So, the number of tickets sold on first day $ = 1094$
Number of tickets sold on second day $ = 1812$
Number of tickets sold on third day $ = 2050$
Number of tickets sold on third day $ = 2751$
Now, we have to find the total number of tickets sold in the four days. So, we have to compute the sum of all the four numbers.
So, we have, $1094 + 1812 + 2050 + 2751$
Grouping the first two and last two terms in order to simplify the calculations, we get,
$ \Rightarrow \left( {1094 + 1812} \right) + \left( {2050 + 2751} \right)$
$ \Rightarrow 2906 + 4801$
$ \Rightarrow 7707$
So, we get the sum of all the four numbers as $7707$.

Hence, the total number of tickets sold at the counter in the four consecutive days is $7707$.

Note:When we combine numbers and variables in a valid way, using operations such as addition, subtraction, multiplication, division, exponentiation, and other operations and functions as yet unlearned, the resulting combination of a mathematical symbol is called a mathematical expression. We must know basic arithmetic such as addition and subtraction of two given numbers in order to find the required answer.