
A black body emits radiations of maximum intensity at 5000 $\buildrel _\circ \over {\mathrm{A}}$ when its temperature is 1227 $^\circ$ C. If its temperature increased by 1000 $^\circ$ C then the maximum intensity of emitted radiation will be at:
(A) 2754.8 $\buildrel _\circ \over {\mathrm{A}}$
(B) 3000 $\buildrel _\circ \over {\mathrm{A}}$
(C) 3500 $\buildrel _\circ \over {\mathrm{A}}$
(D) 4000 $\buildrel _\circ \over {\mathrm{A}}$
Answer
535.8k+ views
Hint: A blackbody also known as perfect emitter or perfect absorber, upon being heated, emits radiation of various wavelengths. The product of maximum wavelength that a blackbody emits and the temperature of a blackbody remains constant.
Formula used:
The maximum wavelength of emission for a black body is related to the temperature of the blackbody by Wien's displacement law as:
$\lambda_m = \dfrac{C}{T}$ .
Complete answer:
We are given that when the given body is at a temperature of 1227$^\circ$ C, the wavelength of the light emitted at maximum intensity is 5000 $\buildrel _\circ \over {\mathrm{A}}$. First, we convert the given temperature in Kelvins.
$1227 + 273 = 1500$K
Then, we determine the constant C, by taking the product of wavelength and temperature:
$C = 5000 \times 1500 = 7.5 \times 10^6 \buildrel _\circ \over {\mathrm{A}}K$ .
Now, as the temperature is increased by 1000 $^\circ$ C, the new temperature becomes 2500 K. The wavelength at this temperature becomes:
$\lambda_m = \dfrac{C}{T}$
$\lambda_m = \dfrac{7.5 \times 10^6 \buildrel _\circ \over {\mathrm{A}} K}{2500 K } = 3000 \buildrel _\circ \over {\mathrm{A}}$ .
Therefore, the correct answer is option (B).
Additional Information:
Blackbody radiation forms an important experiment that was extremely crucial in establishing the most impactful branch in physics called Quantum Mechanics. Quantum mechanics is a branch that deals with the study of microscopic objects and improves our understanding in various branches of physics.
Note:
There are various laws given for blackbody radiation but the one that relates the temperature and the wavelength is Wien's law. The emission spectra of the blackbody is obtained in the continuous form. It peaks at certain wavelengths i.e., when a blackbody is at a certain temperature, it emits light of various wavelengths, the energy density is maximum for certain wavelengths (more intense). Therefore, one should note that we are using the relation for the wavelength of maximum intensity and temperature.
Formula used:
The maximum wavelength of emission for a black body is related to the temperature of the blackbody by Wien's displacement law as:
$\lambda_m = \dfrac{C}{T}$ .
Complete answer:
We are given that when the given body is at a temperature of 1227$^\circ$ C, the wavelength of the light emitted at maximum intensity is 5000 $\buildrel _\circ \over {\mathrm{A}}$. First, we convert the given temperature in Kelvins.
$1227 + 273 = 1500$K
Then, we determine the constant C, by taking the product of wavelength and temperature:
$C = 5000 \times 1500 = 7.5 \times 10^6 \buildrel _\circ \over {\mathrm{A}}K$ .
Now, as the temperature is increased by 1000 $^\circ$ C, the new temperature becomes 2500 K. The wavelength at this temperature becomes:
$\lambda_m = \dfrac{C}{T}$
$\lambda_m = \dfrac{7.5 \times 10^6 \buildrel _\circ \over {\mathrm{A}} K}{2500 K } = 3000 \buildrel _\circ \over {\mathrm{A}}$ .
Therefore, the correct answer is option (B).
Additional Information:
Blackbody radiation forms an important experiment that was extremely crucial in establishing the most impactful branch in physics called Quantum Mechanics. Quantum mechanics is a branch that deals with the study of microscopic objects and improves our understanding in various branches of physics.
Note:
There are various laws given for blackbody radiation but the one that relates the temperature and the wavelength is Wien's law. The emission spectra of the blackbody is obtained in the continuous form. It peaks at certain wavelengths i.e., when a blackbody is at a certain temperature, it emits light of various wavelengths, the energy density is maximum for certain wavelengths (more intense). Therefore, one should note that we are using the relation for the wavelength of maximum intensity and temperature.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a labelled diagram of the human heart and label class 11 biology CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

