A batsman scored 110 runs which includes 3 boundaries and 8 sixes. What percentage of his total score did he make by running between the wickets?
A)$45$ % B)$45\dfrac{5}{{11}}$ % C)$54\dfrac{6}{{11}}$ % D)$55$ %
Answer
644.4k+ views
Hint-First find the total number of scores the batsman made by running between the wickets by subtracting the scores from boundaries and sixes from total scores. Then calculate the percentage of the result obtained.
Complete step-by-step answer:
Given, total score of batsman=$110$ runs and no. of boundaries=$3$ and no. of sixes=$8$
Then runs from the boundaries=$3 \times 4 = 12$ and runs from the sixes=$8 \times 6 = 48$
Now total run by running between the wickets=total score-(score from sixes and boundaries)
Total run by running=$110 - \left( {12 + 48} \right) = 110 - 60 = 50$
So the percentage of total score made by running between the wickets=(total run by running/total score)×100=$\dfrac{{50}}{{110}} \times 100 = \dfrac{{500}}{{11}} = 45\dfrac{5}{{11}}$ %
Hence the correct answer is B.
Note: These types of questions are needed to be observed carefully and then it is easy for the students to guess the method by which the question can be solved. Here, we knew that the run made from boundaries is 4 and sixes is 8. So we easily obtained the runs from 3 boundaries and 8 sixes,which made it easier to solve the question.
Complete step-by-step answer:
Given, total score of batsman=$110$ runs and no. of boundaries=$3$ and no. of sixes=$8$
Then runs from the boundaries=$3 \times 4 = 12$ and runs from the sixes=$8 \times 6 = 48$
Now total run by running between the wickets=total score-(score from sixes and boundaries)
Total run by running=$110 - \left( {12 + 48} \right) = 110 - 60 = 50$
So the percentage of total score made by running between the wickets=(total run by running/total score)×100=$\dfrac{{50}}{{110}} \times 100 = \dfrac{{500}}{{11}} = 45\dfrac{5}{{11}}$ %
Hence the correct answer is B.
Note: These types of questions are needed to be observed carefully and then it is easy for the students to guess the method by which the question can be solved. Here, we knew that the run made from boundaries is 4 and sixes is 8. So we easily obtained the runs from 3 boundaries and 8 sixes,which made it easier to solve the question.
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