
A bar of chocolate cost $Rs.145.63$, a pack of biscuits cost $Rs.92$ and a pack of chips cost $Rs.9.05$. Find the cost of all items.
Answer
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Hint: Total items or summation of all the items can be given as, $Total=a+b+c+......$ for example, summation of cost of 1 pen of 1 rupee and 1 rubber of 2 rupees can be given as, $Total=\text{cost of one pen}\ +\ \text{cost of one rubber}\ =\ 1+2\ =3$ . Now, using this same concept we will solve the problem and find our answer.
Complete step-by-step answer:
In question, we are given the cost of a bar of chocolate, a pack of biscuit and a pack of chips and we are asked to find the total cost of all items, so, to find the total cost of all the three times we will consider bar of chocolate as ‘c’, pack of biscuit as ‘b’ and pack of chips as ’d’ which can be seen mathematically as,
$\text{bar of chocolate,}\ b\ =\ Rs.145.63$
$\text{pack of biscuit,}\ c\ =\ Rs.92$
$\text{pack of chips,}\ d\ =\ Rs.9.05$
Now, total cost of items can be given as,
Total cost of items, $I\ =\ b+c+d$ ………………..………….(i)
Now, instead of adding all the three values together, first we will add any two quantities, here we will add cost of a bar of chocolate and cost of pack of chips, which can be given as,
$b+c\ =145.63+92=Rs.237.63$
Now, we can substitute this value in expression (i) and add the value of pack of chips, so the addition can be given as,
Total cost of items, $I\ =\ 237.63+9.05=Rs.246.68$ .
Thus, we can say that the total cost of all the items is $Rs.246.68$.
Note: Be careful in addition to these decimal numbers. There are chances of calculation error in this problem. Instead of taking 145.63, 9.05 students might take it as 145.36, 9.50 and then it will affect the final answer which will be Rs. 246.86 which will be wrong. So, do not make this mistake.
Complete step-by-step answer:
In question, we are given the cost of a bar of chocolate, a pack of biscuit and a pack of chips and we are asked to find the total cost of all items, so, to find the total cost of all the three times we will consider bar of chocolate as ‘c’, pack of biscuit as ‘b’ and pack of chips as ’d’ which can be seen mathematically as,
$\text{bar of chocolate,}\ b\ =\ Rs.145.63$
$\text{pack of biscuit,}\ c\ =\ Rs.92$
$\text{pack of chips,}\ d\ =\ Rs.9.05$
Now, total cost of items can be given as,
Total cost of items, $I\ =\ b+c+d$ ………………..………….(i)
Now, instead of adding all the three values together, first we will add any two quantities, here we will add cost of a bar of chocolate and cost of pack of chips, which can be given as,
$b+c\ =145.63+92=Rs.237.63$
Now, we can substitute this value in expression (i) and add the value of pack of chips, so the addition can be given as,
Total cost of items, $I\ =\ 237.63+9.05=Rs.246.68$ .
Thus, we can say that the total cost of all the items is $Rs.246.68$.
Note: Be careful in addition to these decimal numbers. There are chances of calculation error in this problem. Instead of taking 145.63, 9.05 students might take it as 145.36, 9.50 and then it will affect the final answer which will be Rs. 246.86 which will be wrong. So, do not make this mistake.
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