Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

A ball falling in a lake of depth $200\,m$ shows $0.1\% $ decrease in its volume at the bottom. What is the bulk modulus of the material of the ball:
A. $19.6 \times {10^8}N{m^{ - 2}}$
B. $19.6 \times {10^{ - 10}}N{m^{ - 2}}$
C. $19.6 \times {10^{10}}N{m^{ - 2}}$
D. $19.6 \times {10^{ - 8}}N{m^{ - 2}}$

Answer
VerifiedVerified
556.8k+ views
Hint:The bulk modulus is one of the measures of the mechanical properties of the solids. Also, the bulk modulus is defined as the ratio of the pressure and the strain. Therefore, we will use the formula of bulk modulus of elasticity to calculate the bulk modulus of the ball.

Formula used:
The formula of the bulk modulus of elasticity is given by
$B = \dfrac{{\Delta P}}{{\dfrac{{\Delta V}}{V}}}$
Here, $B$ is the bulk modulus, $\Delta P$ is the change of the pressure or the force applied per unit area on the material, $\Delta V$ is the change in the volume of the material due to the compression, and $V$ is the initial volume of the material in the units.

Complete step by step answer:
In this example, a ball falls in a lake that is of depth $200\,m$. After falling off the ball, there is a $0.1\% $ decrease in the volume at the bottom.
Now, the formula of the bulk modulus is given by
$B = \dfrac{P}{{\dfrac{{\Delta V}}{V}}}$
Also, the value of the pressure is given by
$P = \rho gh$
$P$ is the pressure, $\rho $ is the density of the liquid, $g$ is the acceleration due to gravity, and $h$ is the height of the liquid.
Also, the decrease in the volume of the lake is given by
$\dfrac{{\Delta V}}{V} = 0.1\% $
$ \Rightarrow \,\dfrac{{\Delta V}}{V} = \dfrac{{0.1}}{{100}}$
Therefore, putting this value in the formula of the bulk modulus as shown below
$B = \dfrac{{\rho gh}}{{0.1\% }}$
$ \Rightarrow \,B = \dfrac{{1000 \times 9.8 \times 200}}{{\dfrac{{0.1}}{{100}}}}$
$ \Rightarrow \,B = \dfrac{{1000 \times 9.8 \times 200 \times 100}}{{0.1}}$
$ \Rightarrow \,B = \dfrac{{19.6 \times {{10}^7}}}{{0.1}}$
$ \Rightarrow \,B = 196 \times {10^7}$
$ \therefore\,B = 19.6 \times {10^8}N{m^{ - 2}}$
Hence, the bulk modulus of the material of the ball is $19.6 \times {10^8}N{m^{ - 2}}$ .

Hence, option A is the correct option.

Note:The bulk modulus of elasticity is one of the measures of the mechanical properties of solids. Other elastic modules include Young’s modulus and Shear modulus. In any case, the bulk elastic properties of a material are used to determine how much it will compress under a given amount of external pressure.