A bag contains Rs.90 in coins. If coins of 50 paise, 25 paise and10 paise are in the ratio 2:3:5, the number of 25 paise coins in the bag is
A. 80
B. 100
C. 120
D. 135
Answer
634.2k+ views
Hint: First we assume that the number of 50 paise , 25 paise and 10 paise coins be 2x , 3x and 5x respectively. After this we will multiply 2x by $\dfrac{1}{2}$ , 3x by $\dfrac{1}{4}$ and 5x by $\dfrac{1}{{10}}$. Finally add them and equate them to 90 to get the equation.
Complete step-by-step answer:
Total value of coins = Rs. 90.
Number of 50 paise coins : Number of 25 paise coins : number of 10 paise coins =2:3:5.
Let the number of 50 paise , 25 paise and 10 paise coins be 2x , 3x and 5x respectively.
We know that :
50 paise = Rs.$\dfrac{1}{2}$
25 paise = Rs.$\dfrac{1}{4}$
10 paise = Rs. $\dfrac{1}{{10}}$.
$\therefore $ Value of 50 paise coins in rupees = Rs.2x$ \times \dfrac{1}{2}$ = Rs. x
Value of 25 paise coins in rupees= Rs. 3x$ \times \dfrac{1}{4} =
{\text{Rs}}{\text{.}}\dfrac{{3{\text{x}}}}{4}$
Value of 25 paise coins in rupees = Rs. 5x$ \times \dfrac{1}{{10}} =
{\text{Rs}}{\text{.}}\dfrac{{\text{x}}}{2}$ .
Total value of coins = Rs.(x+$\dfrac{{3{\text{x}}}}{4} + \dfrac{{\text{x}}}{2}$ )=
Rs.$\dfrac{{9{\text{x}}}}{4}$.
According to question:
$
\dfrac{{9{\text{x}}}}{4} = 90 \\
\Rightarrow {\text{x = }}\dfrac{{90 \times 4}}{9} = 40 \\
$
Therefore, we can say that:
Number of 50 paise coins = 2$ \times $40 = 80.
Number of 25 paise coins = 3$ \times $40 = 120.
Number of 50 paise coins = 5$ \times $40 = 200.
$\therefore $ Number of 25 paise coins = 120.
Therefore, option C is correct.
Note: If the ratio of the quantities are given then the real quantities are obtained by multiplying the individual numbers in the ratio by their common factor. For example if three numbers in ratio are a:b:c the assuming that their common factor is ‘x’, we can write the first number as ‘ax’ , second number as ‘bx’ and third number as ‘cx’. In this question, you have to convert the numbers into their respective value in rupees because the total amount is given in rupees.
Complete step-by-step answer:
Total value of coins = Rs. 90.
Number of 50 paise coins : Number of 25 paise coins : number of 10 paise coins =2:3:5.
Let the number of 50 paise , 25 paise and 10 paise coins be 2x , 3x and 5x respectively.
We know that :
50 paise = Rs.$\dfrac{1}{2}$
25 paise = Rs.$\dfrac{1}{4}$
10 paise = Rs. $\dfrac{1}{{10}}$.
$\therefore $ Value of 50 paise coins in rupees = Rs.2x$ \times \dfrac{1}{2}$ = Rs. x
Value of 25 paise coins in rupees= Rs. 3x$ \times \dfrac{1}{4} =
{\text{Rs}}{\text{.}}\dfrac{{3{\text{x}}}}{4}$
Value of 25 paise coins in rupees = Rs. 5x$ \times \dfrac{1}{{10}} =
{\text{Rs}}{\text{.}}\dfrac{{\text{x}}}{2}$ .
Total value of coins = Rs.(x+$\dfrac{{3{\text{x}}}}{4} + \dfrac{{\text{x}}}{2}$ )=
Rs.$\dfrac{{9{\text{x}}}}{4}$.
According to question:
$
\dfrac{{9{\text{x}}}}{4} = 90 \\
\Rightarrow {\text{x = }}\dfrac{{90 \times 4}}{9} = 40 \\
$
Therefore, we can say that:
Number of 50 paise coins = 2$ \times $40 = 80.
Number of 25 paise coins = 3$ \times $40 = 120.
Number of 50 paise coins = 5$ \times $40 = 200.
$\therefore $ Number of 25 paise coins = 120.
Therefore, option C is correct.
Note: If the ratio of the quantities are given then the real quantities are obtained by multiplying the individual numbers in the ratio by their common factor. For example if three numbers in ratio are a:b:c the assuming that their common factor is ‘x’, we can write the first number as ‘ax’ , second number as ‘bx’ and third number as ‘cx’. In this question, you have to convert the numbers into their respective value in rupees because the total amount is given in rupees.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is deficiency disease class 10 biology CBSE

