Question

A bag contains lemon flavored candies only. Malini takes out one candy without looking into the bag. What is the probability that she takes out?
A) an orange flavored candy?
B) a lemon-flavored candy?

Answer 1

Hint- For solving this question, we have to count the number of orange candies in the bag and lemon candies in the bag. Once, we have the number of different candies in the bag then we can proceed further.
Complete step-by-step answer:
According to the question, only lemon candies are available in the bag. Hence, number of orange flavored candies in the bag $ = 0$
And as all candies are lemon candies only, then no need to worry about the number of lemon candies in the bag as it is also not told in question.
 For the first case, as the bag contains only lemon flavored candies, and nothing else.
 Hence, there are no orange flavored candies in the bag. Hence there is no possibility of taking out an orange candy. In such a case when the number of favourable events is 0 then probability is also 0.
Therefore, the probability of taking out an arrange candy = 0

Now, for the second case as the bag contains only lemon flavored candies, and nothing else.
$\therefore $ Number of favorable outcomes = Total number of possible outcomes

We know that, Probability of an event E = $P(E) = {\dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}}$ = $\dfrac{1}{1} = 1$
Hence, the probability of taking out lemon candy is 1.

Note- This problem is from probability. We need to remember one thing that the probability of any event can not be greater than 1. It always lies between 0 and 1. Also if favourable outcomes is zero then probability is 0 for that event. Probability of any event is given by:
$P(E) = {\dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}}$.