Answer
Verified
449.4k+ views
Hint: We are given earnings of A, B, and C together for each day as Rs. 300. Also, the earning of (A + C) for each day is Rs. 188, we subtract the two to get the earning of B for each day. Once, we have B’s every day earning, we will subtract the value from each day earning of (B + C) and get the earning of C alone.
Complete step-by-step solution:
We are given that the earning of A, B and C together is Rs. 300 per day. That is, we have, (A + B + C)’s one day earning as
\[A+B+C=Rs.300.......\left( i \right)\]
Also, we have that earning of A and C together is Rs. 188 for each day. So, we have,
\[A+C=Rs.188.......\left( ii \right)\]
Now, we will use (i) and (ii) to find the one day earning of B alone. Subtracting (ii) from (i), we get,
\[\left( A+B+C \right)-\left( A+C \right)=B\]
\[\Rightarrow B=Rs.300-Rs.188\]
\[\Rightarrow B=Rs.112\]
So, we get B’s alone per day earning Rs. 112.
We also have the per day earning of (B + C) as Rs. 152.
Therefore, we have,
\[B+C=Rs.152\]
Substituting the value of B in the above equation we get,
\[\Rightarrow Rs.112+C=Rs.152\]
\[\Rightarrow C=Rs.152-Rs.112\]
\[\Rightarrow C=Rs.40\]
So, we get the earning per day of C as Rs. 40.
Hence, option (a) is the right answer.
Note: We first find the per day earning of B alone because it is clubbed with C as per day earning of B + C which is 152. So, once we have B, we can get the daily wages of C by subtracting the daily wages of B from 152. If we go for finding the daily wages of A first, the solution becomes lengthy as we have to find the daily wages of B in the next step.
Complete step-by-step solution:
We are given that the earning of A, B and C together is Rs. 300 per day. That is, we have, (A + B + C)’s one day earning as
\[A+B+C=Rs.300.......\left( i \right)\]
Also, we have that earning of A and C together is Rs. 188 for each day. So, we have,
\[A+C=Rs.188.......\left( ii \right)\]
Now, we will use (i) and (ii) to find the one day earning of B alone. Subtracting (ii) from (i), we get,
\[\left( A+B+C \right)-\left( A+C \right)=B\]
\[\Rightarrow B=Rs.300-Rs.188\]
\[\Rightarrow B=Rs.112\]
So, we get B’s alone per day earning Rs. 112.
We also have the per day earning of (B + C) as Rs. 152.
Therefore, we have,
\[B+C=Rs.152\]
Substituting the value of B in the above equation we get,
\[\Rightarrow Rs.112+C=Rs.152\]
\[\Rightarrow C=Rs.152-Rs.112\]
\[\Rightarrow C=Rs.40\]
So, we get the earning per day of C as Rs. 40.
Hence, option (a) is the right answer.
Note: We first find the per day earning of B alone because it is clubbed with C as per day earning of B + C which is 152. So, once we have B, we can get the daily wages of C by subtracting the daily wages of B from 152. If we go for finding the daily wages of A first, the solution becomes lengthy as we have to find the daily wages of B in the next step.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Difference Between Plant Cell and Animal Cell
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE