
A and B react to form C as $A+B\to C$. The kinetics of reaction is studied and the following data is collected in three separate experiments.
Initial conc. (M)(A) (B) Duration of exp. (hr) Final conc. (A)[A] 0.1 0.5 0.5 0.0975 0.1 2.0 0.5 0.0900 0.05 1.0 2.0 0.0450
The value of the rate constant is:
a.) K = $5 x {{10}^{-2}}{{M}^{-2}}h{{r}^{-1}}or\text{ mo}{{\text{l}}^{-2}}{{L}^{2}}h{{r}^{-1}}$
b.) K = $4 x {{10}^{-3}}{{M}^{-2}}h{{r}^{-1}}or\text{ mo}{{\text{l}}^{-2}}{{L}^{2}}h{{r}^{-1}}$
c.) K = $3 x {{10}^{-3}}{{M}^{-2}}h{{r}^{-1}}or\text{ mo}{{\text{l}}^{-2}}{{L}^{2}}h{{r}^{-1}}$
d.) None of these
| Initial conc. (M)(A) | (B) | Duration of exp. (hr) | Final conc. (A)[A] |
| 0.1 | 0.5 | 0.5 | 0.0975 |
| 0.1 | 2.0 | 0.5 | 0.0900 |
| 0.05 | 1.0 | 2.0 | 0.0450 |
Answer
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Hint: Rate is defined as the speed at which a chemical reaction occurs. Rate is generally expressed in the terms of concentration of reactant which is consumed during the reaction in a unit of time or the concentration of product which is produced during the reaction in a unit of time.
Complete step by step answer:
Rate is defined as the change in concentration of reactant or product with respect to time.
Given reaction: $A+B\to C$
From the first and second experiment we can say that the rate is second order with respect to B
Rate $\alpha {{[B]}^{2}}$
And from the first and second experiment we can say that the rate is first order with respect to A
Rate $\alpha [A]$
The overall order of the reaction will be = 3
Now calculate the value of rate constant i.e. K from experiment 1:
Rate $\alpha [A]{{[B]}^{2}}$
Rate = $K[A]{{[B]}^{2}}$
$5X{{10}^{-3}}=K[0.13]{{[1.0]}^{2}}$
Value of K = K = $5 x {{10}^{-2}}{{M}^{-2}}h{{r}^{-1}}or\text{ mo}{{\text{l}}^{-2}}{{L}^{2}}h{{r}^{-1}}$
So, the correct answer is “Option A”.
Note: The reaction is a third order reaction, the unit for third order reaction is ${{M}^{-2}}h{{r}^{-1}}or\text{ mo}{{\text{l}}^{-2}}{{L}^{2}}h{{r}^{-1}}$. The negative and positive sign in the expression of the rate or reaction only means the change in concentration. A negative charge indicates that the concentration of the reactant is decreasing, similarly a positive charge means that the concentration of product is increasing.
Complete step by step answer:
Rate is defined as the change in concentration of reactant or product with respect to time.
Given reaction: $A+B\to C$
| Initial conc. (M)(A) | (B) | Duration of exp. (hr) | Final conc. (A)[A] | Rate of the reaction |
| 0.1 | 0.5 | 0.5 | 0.0975 | $\dfrac{0.1-0.0975}{0.5}=5X{{10}^{-3}}$ |
| 0.1 | 2.0 | 0.5 | 0.0900 | $\dfrac{0.1-0.0900}{0.5}=2X{{10}^{-3}}$ |
| 0.05 | 1.0 | 2.0 | 0.0450 | $\dfrac{0.1-0.045}{2}=2.5X{{10}^{-3}}$ |
From the first and second experiment we can say that the rate is second order with respect to B
Rate $\alpha {{[B]}^{2}}$
And from the first and second experiment we can say that the rate is first order with respect to A
Rate $\alpha [A]$
The overall order of the reaction will be = 3
Now calculate the value of rate constant i.e. K from experiment 1:
Rate $\alpha [A]{{[B]}^{2}}$
Rate = $K[A]{{[B]}^{2}}$
$5X{{10}^{-3}}=K[0.13]{{[1.0]}^{2}}$
Value of K = K = $5 x {{10}^{-2}}{{M}^{-2}}h{{r}^{-1}}or\text{ mo}{{\text{l}}^{-2}}{{L}^{2}}h{{r}^{-1}}$
So, the correct answer is “Option A”.
Note: The reaction is a third order reaction, the unit for third order reaction is ${{M}^{-2}}h{{r}^{-1}}or\text{ mo}{{\text{l}}^{-2}}{{L}^{2}}h{{r}^{-1}}$. The negative and positive sign in the expression of the rate or reaction only means the change in concentration. A negative charge indicates that the concentration of the reactant is decreasing, similarly a positive charge means that the concentration of product is increasing.
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