A and b are toe smooth light hinges equidistant from c which can slide on abc. The spring force constant k is fixed at its one need c and connected to light rods ad and bd at point d. A block of mass m is suspended at d. Find the velocity when angle cad changes from ${{30}^{0}},{{45}^{0}}$.
Answer
574.2k+ views
Hint: We need to find the effective lengths of the side cd initially and finally as the angle is changed. Next, an energy conservation formula is used for the above question. The total energy of the system initially must be equal to the total energy after the angle is changed.
Complete step by step answer:
The given system can be visualized as follows:
Let us first find out the effective length of the side cd before and after the angle cad is changed,
Initially, the length of side cd will be,
$CD=L\sin {{30}^{0}}=\dfrac{L}{2}$
Next, when the angle is changed, the new length of side cd will be
$CD=L\sin {{45}^{0}}=\dfrac{L}{\sqrt{2}}$
Now, the total energy of the system before the change is equal to,
Spring force+ kinetic energy.
$\dfrac{1}{2}k{{x}^{2}}+\dfrac{1}{2}m{{v}^{2}}$
As the value x in the above formula is the change in the length of the spring,
X will be equal to,
$x=\dfrac{L}{\sqrt{2}}-\dfrac{L}{2}$
Now, the total energy after the change in the angle will be,
$mgx=mg(\dfrac{L}{\sqrt{2}}-\dfrac{L}{2})$
As energy is conserved in the universe,
$\begin{align}
& \dfrac{1}{2}k{{(\dfrac{L}{\sqrt{2}}-\dfrac{L}{2})}^{2}}+\dfrac{1}{2}m{{v}^{2}}=mg(\dfrac{L}{\sqrt{2}}-\dfrac{L}{2}) \\
& \Rightarrow v={{[gL(\sqrt{2}-1)-\dfrac{K{{L}^{2}}}{4m}{{(\sqrt{2}-1)}^{2}}]}^{\dfrac{1}{2}}} \\
\end{align}$
Hence, we can find the velocity of the block in such a way.
Additional information:
Spring is a tool used daily by many of us and their inertia is frequently neglected by assuming it as massless. It’s an extremely casual activity that a spring when strained, undergoes displacement when it is compacted it gets compressed and when it is free it comes to its equilibrium position. This fact tells us that spring exerts an equal as well as an opposite force on a body which compresses or stretches it.
Note: The spring constant will depend on the stiffness of the spring material, the thickness of the wire from which the spring is wound and, the diameter of the ruins of the coil when we deal with a coil spring. The spring content and the length of the spring are inverse proportional to each other. The larger the spring constant, the smaller the extension that a given force creates.
Complete step by step answer:
The given system can be visualized as follows:
Let us first find out the effective length of the side cd before and after the angle cad is changed,
Initially, the length of side cd will be,
$CD=L\sin {{30}^{0}}=\dfrac{L}{2}$
Next, when the angle is changed, the new length of side cd will be
$CD=L\sin {{45}^{0}}=\dfrac{L}{\sqrt{2}}$
Now, the total energy of the system before the change is equal to,
Spring force+ kinetic energy.
$\dfrac{1}{2}k{{x}^{2}}+\dfrac{1}{2}m{{v}^{2}}$
As the value x in the above formula is the change in the length of the spring,
X will be equal to,
$x=\dfrac{L}{\sqrt{2}}-\dfrac{L}{2}$
Now, the total energy after the change in the angle will be,
$mgx=mg(\dfrac{L}{\sqrt{2}}-\dfrac{L}{2})$
As energy is conserved in the universe,
$\begin{align}
& \dfrac{1}{2}k{{(\dfrac{L}{\sqrt{2}}-\dfrac{L}{2})}^{2}}+\dfrac{1}{2}m{{v}^{2}}=mg(\dfrac{L}{\sqrt{2}}-\dfrac{L}{2}) \\
& \Rightarrow v={{[gL(\sqrt{2}-1)-\dfrac{K{{L}^{2}}}{4m}{{(\sqrt{2}-1)}^{2}}]}^{\dfrac{1}{2}}} \\
\end{align}$
Hence, we can find the velocity of the block in such a way.
Additional information:
Spring is a tool used daily by many of us and their inertia is frequently neglected by assuming it as massless. It’s an extremely casual activity that a spring when strained, undergoes displacement when it is compacted it gets compressed and when it is free it comes to its equilibrium position. This fact tells us that spring exerts an equal as well as an opposite force on a body which compresses or stretches it.
Note: The spring constant will depend on the stiffness of the spring material, the thickness of the wire from which the spring is wound and, the diameter of the ruins of the coil when we deal with a coil spring. The spring content and the length of the spring are inverse proportional to each other. The larger the spring constant, the smaller the extension that a given force creates.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

