Question

A 20 Liter container at 400K contains $C{{O}_{2}}(g)$ at pressure 0.4 atm and an excess of SrO. The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when the pressure of $C{{O}_{2}}(g)$ attains its maximum value will be:
Given that - $SrC{{O}_{3}}(s)\to SrO(s)+C{{O}_{2}}$

Answer 1

Hint: Before answering this question, we should first know about the ideal gas law. The representation of it is $PV=nRT$. This law was the coming together of four laws that are Boyle’s law, Charle’s law, Avogadro’s law, and Gay lussac law.

Complete answer:
The other name is ideal gas law is a general gas equation. It is the equation that represents the state of the hypothetical ideal gas. It determines the behavior of various gases with certain conditions but the drawback is that it has certain limitations. Benoit Paul Emile gave this equation in 1834, This law can be written as –
$PV=nRT$
Where P is the pressure, V is the volume of gas, n is the amount of substance, R is gas constant and T is the temperature of a gas.
One of the Kinetic gas theory postulates stated that there is no change in the kinetic energy into any other form of energy of the gas molecules. It remains the same before and after the collision. It is unchanged.
Ideas gas equation defines the states of the hypothetical gases that are expressed mathematically when empirical and physical constants are combined. It is also known as the general gas equation.
$SrC{{O}_{3}}(s)\to \,SrO(s)+C{{O}_{2}}$
${{K}_{p}}=P{{O}_{C{{O}_{2}}}}$= 1.6 atm = maximum pressure
Volume container at this stage
$V=\dfrac{nRT}{P}$
As the container is sealed, so n= constant
$V=\dfrac{0.4\times 20}{1.6}$
     $=5L$

Note:
Limitations of the ideal gas equation are-
It Only holds until the density is low.
It considers the force of attraction between gas molecules to be 0.