Question

A 10 L of ${{N}_{2}}$ and 30 L of ${{H}_{2}}$ combine to form $N{{H}_{3}}$ having volume of:
(a)- 20 L
(b)- 40 L
(c)- 30 L
(d)- 10 L

Answer 1

Hint:In the question, the ammonia is produced from hydrogen gas and nitrogen gas, this is called Haber’s process, from the equation of Haber’s process we can calculate the volume of the ammonia produced.

Complete step-by-step answer:As we can see that in the question, the ammonia is produced from hydrogen gas and nitrogen gas, so the process in which the ammonia is produced from hydrogen gas and nitrogen gas then it is known as Haber's process. The equation given in Haber's process is:
${{N}_{2}}+3{{H}_{2}}\to 2N{{H}_{3}}$
We can see that one mole of nitrogen gas and three moles of hydrogen gas combine to form 2 moles of ammonia. So, the amount of ammonia produced is equal to double the amount of nitrogen gas taken.
So, in the question, the volume of nitrogen gas taken is 10 L, so by doubling this volume we can find the volume of ammonia produced.
Volume of $N{{H}_{3}}$ = 2 x 10 = 20 L
So, the amount of ammonia produced will be 20 L.
As this reaction has a negative value of $\Delta H$, that is equal to -91.8 KJ /mol, which means that energy is evolved in the reaction and hence it is an exothermic reaction.

Therefore, the correct answer is an option (a)- 20 L.

Note:For the reaction to occur there are some conditions that must be followed like the pressure must be 200 atm, the temperature must be around 400 – 450 degrees Celsius, and the catalyst must be iron.