A 1.0 HP motor pumps out water from a well of depth 20 meters and fills a water tank of volume 2238 liters at the height of 10 meters from the ground. The running time of the motor to fill the empty water tank is: \[\left( {g = 10m{s^{ - 2}}} \right)\]
A. 5 minutes
B. 10 minutes
C. 15 minutes
D. 20 minutes
Answer
603.3k+ views
Hint: Specific pump power is the measurement of electric power needed to operate a pump, relative to the volume flow rate. Also, \[1{\text{ }}hp = 746{\text{ }}Watts\]
In this question, the power of the motor is given, which is transferring the water from a well to a water tank. First, find the total potential energy required to transfer the water to 10+20=30m height from the well then find the time required.
Complete step by step answer:
Pump of \[1{\text{ }}hp = 746{\text{ }}Watts\] and the depth of the well is 20 meters.
Work done by a motor is equal to the change in the potential energy of water when it is pumped from the well to the overhead tank, where work done is given as, \[W = P * t\]
Now assume the total time to fill the tank to be $t$ seconds.
The total height the water is pumped is given as: \[10 + 20 = 30{\text{ }}m\]
Now use the work done formula
\[
W = P \times t \\
= 746 \times t \\
\]
The mass of the water, whose density is \[1\dfrac{{kg}}{{{m^3}}}\]
\[
m = density \times volume \\
= 1\dfrac{{Kg}}{{{m^3}}} \times 2238{m^3} \\
= 2238Kg \\
\]
So the potential energy will be
\[
PE = mgh \\
= 2238 \times 10 \times 30 \\
= 671400J \\
\]
As per energy conservation rule work done by a motor is equal to the change in the potential energy of water; hence we can write
\[
W = PE \\
746 \times t = 671400 \\
t = \dfrac{{671400}}{{745}} \\
= 900\sec \\
= 15\min \\
\]
The total running time of the motor to fill the empty water tank is \[15\min \]
So, the correct answer is “Option C”.
Note:
The potential energy is the same as the work done in the same way kinetic energy is. Potential energy is a way of storing energy as of virtue of its motion while work is done is the way of changing energy from one form to another.
In this question, the power of the motor is given, which is transferring the water from a well to a water tank. First, find the total potential energy required to transfer the water to 10+20=30m height from the well then find the time required.
Complete step by step answer:
Pump of \[1{\text{ }}hp = 746{\text{ }}Watts\] and the depth of the well is 20 meters.
Work done by a motor is equal to the change in the potential energy of water when it is pumped from the well to the overhead tank, where work done is given as, \[W = P * t\]
Now assume the total time to fill the tank to be $t$ seconds.
The total height the water is pumped is given as: \[10 + 20 = 30{\text{ }}m\]
Now use the work done formula
\[
W = P \times t \\
= 746 \times t \\
\]
The mass of the water, whose density is \[1\dfrac{{kg}}{{{m^3}}}\]
\[
m = density \times volume \\
= 1\dfrac{{Kg}}{{{m^3}}} \times 2238{m^3} \\
= 2238Kg \\
\]
So the potential energy will be
\[
PE = mgh \\
= 2238 \times 10 \times 30 \\
= 671400J \\
\]
As per energy conservation rule work done by a motor is equal to the change in the potential energy of water; hence we can write
\[
W = PE \\
746 \times t = 671400 \\
t = \dfrac{{671400}}{{745}} \\
= 900\sec \\
= 15\min \\
\]
The total running time of the motor to fill the empty water tank is \[15\min \]
So, the correct answer is “Option C”.
Note:
The potential energy is the same as the work done in the same way kinetic energy is. Potential energy is a way of storing energy as of virtue of its motion while work is done is the way of changing energy from one form to another.
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