
a × (-1) = - 30. Is the integer ‘a’ a positive integer or a negative integer?
Answer
585.9k+ views
Hint: Now we are given with $a \times (-1) = -30$. Here we are multiplying a negative number to a and we get a negative number. Now if we multiply a negative number with a positive number then we get a negative number. Hence we can say that a is a positive number.
Complete step-by-step solution:
Now we have the given equation as $a \times (-1) = - 30$.
Now first let us consider is that ‘a’ is a negative integer
Now we know that $(-) \times(-) = (+)$.
For example: $-3 \times - 2 = 6$.
Now here if a is negative and (-1) is also negative hence the product will be positive.
But we have a product at - 30. Which is negative.
Hence a cannot be positive.
Now first let us consider is that ‘a’ is a positive integer.
Now we know that $(+)\times (-) = (-)$.
For example $3 \times (-2) = - 6$.
Now here if a is positive and (-1) is also negative hence the product will be negative.
Here we have a product as - 30. Which is negative.
Hence ‘a’ is positive.
Note: Now we are given with the equation a × (-1) = - 30. Now multiplying the equation by – 1 we get, a = 30. Hence we find the value of a and this is positive. Hence we get that ‘a’ is positive.
Complete step-by-step solution:
Now we have the given equation as $a \times (-1) = - 30$.
Now first let us consider is that ‘a’ is a negative integer
Now we know that $(-) \times(-) = (+)$.
For example: $-3 \times - 2 = 6$.
Now here if a is negative and (-1) is also negative hence the product will be positive.
But we have a product at - 30. Which is negative.
Hence a cannot be positive.
Now first let us consider is that ‘a’ is a positive integer.
Now we know that $(+)\times (-) = (-)$.
For example $3 \times (-2) = - 6$.
Now here if a is positive and (-1) is also negative hence the product will be negative.
Here we have a product as - 30. Which is negative.
Hence ‘a’ is positive.
Note: Now we are given with the equation a × (-1) = - 30. Now multiplying the equation by – 1 we get, a = 30. Hence we find the value of a and this is positive. Hence we get that ‘a’ is positive.
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