Question

7g of CO on complete oxidation produces the following weight of $C{{O}_{2}}$ :
A. 14
B. 11
C. 42
D. 30

Answer 1

Hint: Here, we can see that the process of oxidation is taking place, when carbon monoxide is reacted with oxygen to produce carbon dioxide. Basically, oxidation reaction is one in which loss of electrons takes place or we can say gain of oxygen takes place.

Complete Solution :
- As we know that CO when reacted with oxygen produces carbon dioxide. We can write the reaction that takes place as:
\[2CO+{{O}_{2}}\to 2C{{O}_{2}}\]

- Now, let us take out the molecular weight of the reactants and products in the above reaction.
- The molecular weight of 2CO will be:
\[\begin{align}
 & 2CO \\
 & = 2\times (12 + 16) \\
 & = 2\times 28 \\
 & = 56 \\
\end{align}\]

- The molecular weight of ${{O}_{2}}$ will be:
\[\begin{align}
 & {{O}_{2}} \\
 & =16\times 2 \\
 & =32 \\
\end{align}\]

- The molecular weight of $2C{{O}_{2}}$ will be:
\[\begin{align}
 & 2C{{O}_{2}} \\
 & =2\times \left( 12+\left( 2\times 16 \right) \right) \\
 & =2\times \left( 12+32 \right) \\
 & =2\times 44 \\
 & =88 \\
\end{align}\]

- We can see here that 56 g of CO reacts with 32 g of oxygen to form 88 g of $C{{O}_{2}}$
- Therefore, we can say that 7 g of CO reacts with oxygen to form:
$\dfrac{88}{56}\times 7$
= 11 g of $C{{O}_{2}}$
- Hence, we can conclude that the correct option is (b), that is 7g of CO on complete oxidation produces 11 g weight of $C{{O}_{2}}$
So, the correct answer is “Option B”.

Note: - As we know that the existence of carbon dioxide gas in the atmosphere prohibits the transfer of any energy that is obtained from the earth, that results in the greenhouse effect.
- We should not get confused in terms of oxidation and reduction. As in oxidation loss of electrons takes place or we can say gain of oxygen takes place. Whereas, in reduction, gain of electrons takes place or we can say gain of hydrogen takes place.