5 persons are sitting at a round table in such a way that Tallest person is always on the right side of the shortest person. The number of such arrangements is
A. $6$
B. $8$
C. $24$
D. None of these
Answer
589.8k+ views
Hint: In this problem we need to find the number of possible arrangements that are possible according to the given conditions. We have given that $5$ persons are sitting in a round table and out of them we can observe there is one tall person and one short person. We need to arrange them in an order so that the tallest person is always on the right side of the shortest person. So, we will use the concept of the permutation and use the formulas of permutation to get the required result.
Complete step by step answer:
Given that $5$ persons are sitting at a round table.
From the problem statement we can observe that there should be a tallest person along with the shortest person.
So, we will assume the $5$ persons as $A$, $B$, $C$, $T$, $S$. Where $T$ represents the tallest person and $S$ represents the shortest person.
The arrangement of the $5$ persons in a round table such that tallest person is always right of the shortest person is given by
From the above arrangement we can observe that we need to arrange $4$ peoples in a round table.
All similar possible arrangements by using the concept of permutation and combinations are given by
$\left( 4-1 \right)!=3!$
We have the value of $3!$ as $3\times 2\times 1=6$.
Hence the number of possible arrangements is $6$.
So, the correct answer is “Option A”.
Note: In this problem we have given that the people sit in a round table so we have noted the number of possible ways as $\left( n-1 \right)!$. If they have mentioned that the people will sit in a straight table then the number of possible ways is given by $n!$.
Complete step by step answer:
Given that $5$ persons are sitting at a round table.
From the problem statement we can observe that there should be a tallest person along with the shortest person.
So, we will assume the $5$ persons as $A$, $B$, $C$, $T$, $S$. Where $T$ represents the tallest person and $S$ represents the shortest person.
The arrangement of the $5$ persons in a round table such that tallest person is always right of the shortest person is given by
From the above arrangement we can observe that we need to arrange $4$ peoples in a round table.
All similar possible arrangements by using the concept of permutation and combinations are given by
$\left( 4-1 \right)!=3!$
We have the value of $3!$ as $3\times 2\times 1=6$.
Hence the number of possible arrangements is $6$.
So, the correct answer is “Option A”.
Note: In this problem we have given that the people sit in a round table so we have noted the number of possible ways as $\left( n-1 \right)!$. If they have mentioned that the people will sit in a straight table then the number of possible ways is given by $n!$.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

