Question

\[2PbO\left( s \right) + C\left( s \right) \to 2Pb\left( s \right) + CO2\left( g \right)\]
Which of the following statements are correct for the above chemical reaction?
a) Lead is reduced
b) Carbon dioxide is oxidized
c) Carbon is oxidized
d) Lead oxide is reduced
A) \[\;\left( a \right){\text{ }}and{\text{ }}\left( b \right)\]
B) \[\left( a \right){\text{ }}and{\text{ }}\left( c \right)\]
C) \[\;\left( a \right),{\text{ }}\left( b \right){\text{ }}and{\text{ }}\left( c \right)\]
D) All

Answer 1

Hint: Oxidation and reduction both can be explained in terms of oxygen transfer. Oxidation is the process in which oxygen is added to a compound. Reduction is the process in which oxygen is removed from a compound. In a reaction where both oxidation and reduction occur at the same time, that kind of reaction is called a redox reaction.

Complete step-by-step answer:
When we talk about oxidizing agents, we must know that it is a substance which oxidizes something else. They do this by going under the reduction process themselves. Reducing agents are those who reduce something else. Oxidising agents give oxygen to another substance which reduces agents that take oxygen from another substance.

Also oxidation is known to be the loss of electrons and reduction is known to be the gain of electrons. This can be termed into acronym: \[OIL{\text{ }}RIG\]
\[OIL = \]Oxidation is loss
\[RIG = \]reduction is gain.

We must know that in the above equation \[PbO\] is reduced to \[Pb\] and the Carbon atom gets oxidised to carbon dioxide. Hence, statements \[\;\left( a \right){\text{ }}and{\text{ }}\left( b \right)\] are correct.

Thus, the correct answer is option ‘A’.

Note: When we talk about oxidation in terms of hydrogen, we must know that it is the loss of hydrogen. Reduction is known to be the gain of hydrogen. An oxidizing agent will be required to remove the hydrogen from the other substance. A commonly used oxidizing agent is potassium dichromate \[\left( {VI} \right)\] solution acidified with dilute sulfuric acid. A possible reducing agent is sodium tetrahydridoborate, \[NaB{H_4}\].