Questions & Answers

Question

Answers

a) 16

b) 32

c) 48

d) 64

Answer
Verified

We know that equivalent weight is the mass of one equivalent, that is the mass of a given substance which will combine with or displace a fixed quantity of another substance.

And in the question it is given that 2.8g of iron (Fe) displaces 3.2g of copper (Cu) from a solution of copper sulphate (\[CuS{{O}_{4}}\]).

Then for finding the equivalent mass of copper:

Let,

W = mass displaced, E = equivalent mass.

Then we know that equivalent amount displaced and occupied will be equal:

\[\dfrac{{{W}_{Cu}}}{{{E}_{Cu}}}=\dfrac{{{W}_{Fe}}}{{{E}_{Fe}}}\]

By putting all the given data in above equation:

\[\dfrac{3.2}{{{E}_{Cu}}}=\dfrac{2.8}{28}\]

By solving the above equation:

\[\dfrac{3.2}{{{E}_{Cu}}}\]= 0.1,

Then,

\[{{E}_{Cu}}\](Equivalent mass of the copper (Cu) = (3.2 / 0.1)

\[{{E}_{Cu}}\]= 32 g/eq.

So, the equivalent weight of copper (Cu) is 32.

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