
\[252{\text{ }}grams\] of oxalic acid with molecular formula \[{C_2}{H_2}{O_4}.2{H_2}O\] dissolved in water to form 250ml. of the solution. Its molarity will be:
\[
{A.{\text{ }}16M} \\
{B.{\text{ }}8M} \\
{C.{\text{ }}32M} \\
{D.{\text{ }}24M}
\]
Answer
583.5k+ views
Hint: We have to calculate the number of moles of oxalic acid and then divide it by amount of water in litre.
Formula Used: \[Molarity{\text{ }}\left( M \right)\; = {\text{ }}\dfrac{{Number{\text{ }}of{\text{ }}moles{\text{ }}of{\text{ }}solute}}{{Volume{\text{ }}of{\text{ }}solution{\text{ }}in{\text{ }}liters}}\]
Complete step by step solution:
Let’s start with discussing the concept of molarity, molarity is defines as the number of moles in solute per litre of solution. It is also termed as molar concentration of a solution.
We are given with \[252{\text{ }}g\] of oxalic acid; also we can calculate the molar mass of oxalic acid from its molecular formula. Molecular formula of oxalic acid is \[{C_2}{H_2}{O_4}.2{H_2}O\] and the molar weight of each atom present is \[C = 12g,{\text{ }}H = 1g,{\text{ }}O = 16g\]
Molar mass of oxalic acid\[ = {\text{ }}\left( {12{\text{ }}X{\text{ }}2} \right){\text{ }} + {\text{ }}\left( {1{\text{ }}X{\text{ }}2} \right){\text{ }} + {\text{ }}\left( {16{\text{ }}X{\text{ }}4} \right){\text{ }} + {\text{ }}\left( {18{\text{ }}X{\text{ }}2} \right){\text{ }} = {\text{ }}126{\text{ }}grams\]
So, 1 mole of oxalic acid is having a mass of\[126{\text{ }}grams\].
Let’s calculate the number of moles of oxalic acid present in \[252g\] of oxalic acid.
Moles of oxalic acid = $\dfrac{{Given{\text{ }}mass}}{{Molar{\text{ }}mass}} = \dfrac{{252}}{{126}} = 2{\text{ }}moles$
Now, we are having 2 moles of oxalic acid in \[250{\text{ }}ml\]of water. We can write \[250{\text{ }}ml\] as \[0.25{\text{ }}litre\]of water. So, the molarity of the solution will be given by
\[Molarity{\text{ }}\left( M \right)\; = {\text{ }}\dfrac{{Number{\text{ }}of{\text{ }}moles{\text{ }}of{\text{ }}solute}}{{Volume{\text{ }}of{\text{ }}solution{\text{ }}in{\text{ }}liters}}\]
Molarity of solution = $\dfrac{2}{{0.25}} = 8{\text{ }}M$
So, we can conclude that the answer to this question is option B. \[8{\text{ }}M\]
Note: We must know that molarity is the concept which is widely used in chemistry and related fields. It is used to develop a particular solution of defined concentration. These solutions are made in a volumetric flask and are used in various experiments. In short, the concept of molarity is a very important concept from a practical point of view.
Formula Used: \[Molarity{\text{ }}\left( M \right)\; = {\text{ }}\dfrac{{Number{\text{ }}of{\text{ }}moles{\text{ }}of{\text{ }}solute}}{{Volume{\text{ }}of{\text{ }}solution{\text{ }}in{\text{ }}liters}}\]
Complete step by step solution:
Let’s start with discussing the concept of molarity, molarity is defines as the number of moles in solute per litre of solution. It is also termed as molar concentration of a solution.
We are given with \[252{\text{ }}g\] of oxalic acid; also we can calculate the molar mass of oxalic acid from its molecular formula. Molecular formula of oxalic acid is \[{C_2}{H_2}{O_4}.2{H_2}O\] and the molar weight of each atom present is \[C = 12g,{\text{ }}H = 1g,{\text{ }}O = 16g\]
Molar mass of oxalic acid\[ = {\text{ }}\left( {12{\text{ }}X{\text{ }}2} \right){\text{ }} + {\text{ }}\left( {1{\text{ }}X{\text{ }}2} \right){\text{ }} + {\text{ }}\left( {16{\text{ }}X{\text{ }}4} \right){\text{ }} + {\text{ }}\left( {18{\text{ }}X{\text{ }}2} \right){\text{ }} = {\text{ }}126{\text{ }}grams\]
So, 1 mole of oxalic acid is having a mass of\[126{\text{ }}grams\].
Let’s calculate the number of moles of oxalic acid present in \[252g\] of oxalic acid.
Moles of oxalic acid = $\dfrac{{Given{\text{ }}mass}}{{Molar{\text{ }}mass}} = \dfrac{{252}}{{126}} = 2{\text{ }}moles$
Now, we are having 2 moles of oxalic acid in \[250{\text{ }}ml\]of water. We can write \[250{\text{ }}ml\] as \[0.25{\text{ }}litre\]of water. So, the molarity of the solution will be given by
\[Molarity{\text{ }}\left( M \right)\; = {\text{ }}\dfrac{{Number{\text{ }}of{\text{ }}moles{\text{ }}of{\text{ }}solute}}{{Volume{\text{ }}of{\text{ }}solution{\text{ }}in{\text{ }}liters}}\]
Molarity of solution = $\dfrac{2}{{0.25}} = 8{\text{ }}M$
So, we can conclude that the answer to this question is option B. \[8{\text{ }}M\]
Note: We must know that molarity is the concept which is widely used in chemistry and related fields. It is used to develop a particular solution of defined concentration. These solutions are made in a volumetric flask and are used in various experiments. In short, the concept of molarity is a very important concept from a practical point of view.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is boron A Nonmetal B Metal C Metalloid D All class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

Distinguish between verbal and nonverbal communica class 11 english CBSE

