Question

2 liters of sample of ${{H}_{2}}{{O}_{2}}$ give 22.4 liters of ${{O}_{2}}$ at S.T.P. Normality of given ${{H}_{2}}{{O}_{2}}$ sample is ‘X’.

Answer 1

Hint: First we have to find out the strength of the given ${{H}_{2}}{{O}_{2}}$ sample by apply Avogadro’s law which states that, one of mole of gas occupies 22.4 liters of volume at S.T.P and N.T.P and by using the normality formula of ${{H}_{2}}{{O}_{2}}$ as ;$Normality={Volume\text{ }strength}{5.6}$, we can easily calculate its normality. Now solve it.

Complete step by step solution:
- First of all, let’s discuss what is normality. By the term normality , we mean the total no of moles of gram equivalent dissolved in 1 litre of the solution and the normality is represented by the symbol as N. The normality of ${{H}_{2}}{{O}_{2}}$ can be directly found by using the formula as:
$Normality={Volume\text{ }strength} \times {5.6}$
- This numerical is based on the Avogadro’s law which states that the one mole of the gas occupies 22.4 liters of volume at S.T.P. or N.T.P
Now considering the numerical;
2 liters of sample of ${{H}_{2}}{{O}_{2}}$ give = $22.4\text{ }liters$ of ${{O}_{2}}$ at S.T.P. ( given)
Then,
1 liters of sample of ${{H}_{2}}{{O}_{2}}$ give =${22.4}{2}\text{ }liters$ of ${{O}_{2}}$ at S.T.P.
= $11.2\text{ }liters$ of ${{O}_{2}}$ at S.T.P.
Now, by applying the normality formula for ${{H}_{2}}{{O}_{2}}$,we can easily find its normality as;
$Normality={Volume\text{ }strength} \times {5.6}$-----------(1)
Volume strength =$11.4\text{ }liters$ of ${{O}_{2}}$ at S.T.P.
Normality = X (given)
Put all these values in equation (1), we get;
$\begin{align}
& X={11.4}\times{5.6} \\
& \text{ = 2 N} \\
\end{align}$

Therefore, 2 liters of sample of ${{H}_{2}}{{O}_{2}}$ which gives 22.4 liters of ${{O}_{2}}$ at S.T.P. has the Normality as $2\text{ }N$.

Note: Avogadro’s law is only applicable under standard conditions of temperature and pressure i.e. at 1 atmosphere pressure and 273 K temperature and if these conditions are not satisfied , then this law is not applicable in those conditions.