Question

$1N$ is nearly equal to ?
\[{\text{A}}{\text{.0}}{\text{.1 kg - f}}\]
\[{\text{B}}{\text{.1 kg - f}}\]
\[{\text{C}}{\text{.}}\dfrac{1}{{19.8}}{\text{ kg - f}}\]
\[{\text{D}}{\text{.9}}{\text{.8 kg - f}}\]

Answer 1

Hint: To solve the given question,we use the concepts of force and weight .Using weight equation we take relation between kg and newton.We assume a body is being dropped from height above ground level with velocity zero to find find and convert it to newton further we take reciprocal to find newton in terms of weight.

Complete step by step answer:
We cannot actually convert Kg to Newton, because Newton is a unit of Force whereas Kg is the unit of mass respectively. Conversion of units can be done for two identical scales but not for two different physical scales. So, we can give relation for the two units, saying conversion of them will be the wrong term.
When an object is dropped from a certain height above the ground level, it will experience a force purely due to the acceleration due to gravity. While free fall the object will experience a force and the force experienced is known as Weight of the body/object and mathematically is given by:
\[W = mg\]
Now we can give a relation between Newton and kg by analyzing how many Kg in one Newton. Let us assume that a 1Kg mass is dropped from a height above ground level with an initial velocity zero then the force experienced by the object is,
\[W = 1kg \times 9.81m/{s^2} = 9.81N\]
From the discussion of the relation between Kg and Newton, we have concluded that they are directly proportional to each other. Therefore, we write:
\[1kg - f = 9.81N\]
From the relation between Kg-f and Newton we have,
\[1N = \dfrac{1}{{9.81}}kg - f = 0.102kg - f\]
Therefore, option (A) is correct.

Note:
Newton is the SI unit of Force. It is defined as- the force required to accelerate an object of the mass of 1 kilogram (1kg) by \[1m/{s^2}\] in the direction of applied force. In the CGS system, \[1N\] is equal to \[{10^5}\] Dyne. Dyne is the unit of Force in the CGS system.