Question

When 1L of $C{{O}_{2}}$is heated with graphite, the volume of the gas collected is 1.5 L. Calculate the number of moles of $CO$produced at STP.
A. $\dfrac{1}{11.2}$
B. $\dfrac{28}{22.4}$
C. $\dfrac{1}{22.4}$
D. $\dfrac{14}{22.4}$

Answer 1

Hint: Mole is represented by the symbol mol which is defined as the unit of measurement for amount of substance in the SI units where SI stands for International System of Units. It can also be defined as exactly $6.022140796\times {{10}^{23}}$particles which may be atoms, molecules, ions or electrons.

Complete answer:
The number $6.022140796\times {{10}^{23}}$ is the number known by the name Avogadro’s number which define mass of one mole of a chemical compound in grams is numerically equal and the term mole is used in chemistry as a convenient way to express amounts of reactants and products of chemical reaction. Here the reaction of carbon dioxide with graphite is shown as:
$C{{O}_{2}}(g)+C(s)\to 2CO(g)$

1L	0	0; of $C{{O}_{2}}$consumed
1-x		2x; x is amount

This implies (1-x) + 2x = Total volume which is 1.5 x (Given)
Now the value of x would be 0.5 L.
So, amount of $CO$ consumed = 1 L
We know that according to STP conditions 1 mole of $C{{O}_{2}}$$\to $ 22.4 L $CO$(g)
Therefore y $\to $ 1 L $CO$
Which gives the value of y = $\dfrac{1}{22.4}$moles of $CO$
Hence this implies that the number of moles of $CO$ produced at STP will be $\dfrac{1}{22.4}$.

Hence, Option C is the correct answer.

Note:
STP stands for standard temperature and pressure and it can be defined as a temperature 273.15 K and an absolute pressure exactly equal to 100 kpa where temperature units K implies kelvin and pressure unit kpa represents kilo Pascal.