
What is $1.3 \times 10$ to the 0 power?
Answer
467.4k+ views
Hint: As we can see the question belongs to the zero power rule, as we know that any number that contains 0 as an exponent will be atlast equal to 1. And then we will go for the final solution.
Complete step by step answer:
As per the question, we can also write $1.3 \times 10$ to the 0 power as $1.3 \times {10^0}$. So, as we can see in the above term, 10 has its power as 0, which is something different. ${10^0}$ belongs to the Zero power rule or the rule for zero as exponent: Any nonzero real number raised to the power of zero is one, this means anything that looks like ${a^0}$ will always equal 1 if a is not equal to zero.
Now, solve for the given term-
$1.3 \times {10^0} = 1.3 \times 1\,\,(\because {10^0} = 1) \\ $
$\therefore 1.3 \times {10^0} = 1.3$
In a nutshell, the multiplicative identity is 1, because \[1 \times x = x\] for every other number $x$ . Because any number to the zero power is simply the product of no numbers at all, which is the multiplicative identity, 1, any number to the zero power is one.0 to the power of anything else, on the other hand, is 0 because no matter how many times you multiply nothing by nothing, you get nothing.
Therefore, after solving for the given term $1.3 \times {10^0}$ , we get 1.3 as the final solution.
Note: In scientific notation, we write a number so that it has a single digit to the left of the decimal sign and is multiplied by an integer power of 10. In scientific notation, a number is written as $a \times {10^n}$ , where \[1 \leqslant a < 10\;\] and $n$ is an integer and \[1 \leqslant a < 10\;\]. Simply multiply by the power ${10^n}$ (or divide if n is negative) to write the number in normal or standard notation. When multiplying by ${10^n}$ , this implies moving decimal $n$ digits to the right, and when dividing by ${10^n}$ (i.e. multiplying by ${10^{ - n}}$ ), this means moving decimal $n$ digits to the left.
In the given case, as we have the number as $1.3 \times {10^0}$ we need not move the decimal digit to either side and hence in standard notation \[1.3 \times {10^0} = 1.3\] itself.
Complete step by step answer:
As per the question, we can also write $1.3 \times 10$ to the 0 power as $1.3 \times {10^0}$. So, as we can see in the above term, 10 has its power as 0, which is something different. ${10^0}$ belongs to the Zero power rule or the rule for zero as exponent: Any nonzero real number raised to the power of zero is one, this means anything that looks like ${a^0}$ will always equal 1 if a is not equal to zero.
Now, solve for the given term-
$1.3 \times {10^0} = 1.3 \times 1\,\,(\because {10^0} = 1) \\ $
$\therefore 1.3 \times {10^0} = 1.3$
In a nutshell, the multiplicative identity is 1, because \[1 \times x = x\] for every other number $x$ . Because any number to the zero power is simply the product of no numbers at all, which is the multiplicative identity, 1, any number to the zero power is one.0 to the power of anything else, on the other hand, is 0 because no matter how many times you multiply nothing by nothing, you get nothing.
Therefore, after solving for the given term $1.3 \times {10^0}$ , we get 1.3 as the final solution.
Note: In scientific notation, we write a number so that it has a single digit to the left of the decimal sign and is multiplied by an integer power of 10. In scientific notation, a number is written as $a \times {10^n}$ , where \[1 \leqslant a < 10\;\] and $n$ is an integer and \[1 \leqslant a < 10\;\]. Simply multiply by the power ${10^n}$ (or divide if n is negative) to write the number in normal or standard notation. When multiplying by ${10^n}$ , this implies moving decimal $n$ digits to the right, and when dividing by ${10^n}$ (i.e. multiplying by ${10^{ - n}}$ ), this means moving decimal $n$ digits to the left.
In the given case, as we have the number as $1.3 \times {10^0}$ we need not move the decimal digit to either side and hence in standard notation \[1.3 \times {10^0} = 1.3\] itself.
Recently Updated Pages
Questions & Answers - Ask your doubts

A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Two Planoconcave lenses 1 and 2 of glass of refractive class 12 physics CBSE

The compound 2 methyl 2 butene on reaction with NaIO4 class 12 chemistry CBSE

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Name the states through which the Tropic of Cancer class 8 social science CBSE

Full form of STD, ISD and PCO

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE

Summary of the poem Where the Mind is Without Fear class 8 english CBSE


