
You are dealt one card from a standard 52-card deck. How do you find the probability of being dealt a two?
Answer
556.5k+ views
Hint: In this problem, we have to find the probability for ‘two’ cards which can be drawn from a deck of 52 cards. There are a total four cards of number two. So we can easily find the probability. Formula for the probability is:
P(any event) = $\dfrac{Number\text{ }of\text{ }favourable\text{ outcomes}}{Total\text{ }Number\text{ }of\text{ }favourable\text{ outcomes}}$
Complete step by step answer:
Now, let’s discuss the problem.
Do you play with cards? If not then let’s know about these cards. You can play interesting games with these cards. The whole deck consists of 52 cards. It contains 4 suits each having 13 cards in it. These are spades, hearts, diamonds and clubs. Colour of spades and clubs are black while hearts and diamonds are red. Now, if we talk about one particular suit, it contains ace, king, queen, jack or knaves, 10, 9, 8, 7, 6, 5, 4, 3, and 2. The cards of King, Queen, and Jack (or Knaves) are called the face cards. So, in the whole deck, there are 12 face cards. Now, we will know what is probability and how it is applied on this deck of cards. Probability shows how likely an event can happen or we can say that how many chances are there for an event to take place. Probability of an event is given as:
P(any event E) = $\dfrac{Number\text{ }of\text{ }favourable\text{ outcomes of E}}{Total\text{ }Number\text{ }of\text{ }favourable\text{ outcomes of E}}$
For this question,
There are four cards for number ‘two’ that means there are four ways of getting two. So the total number of ways in which this event can occur is 4. And we already know that the total number of cards in a deck is 52. So 52 will be the total favourable outcomes. So,
P(getting two) = $\dfrac{4}{52}=\dfrac{1}{13}$
This is the final answer.
Note:
We have to find the probability of two from 52 cards not 13 cards. Students usually make such mistakes because they think that each suit contains 13 cards so probability will also be found for 13 cards itself. After applying formula, reduce the fraction in the simplest form. And do remember that the probability of any event cannot be greater than 1 and it also cannot be negative.
P(any event) = $\dfrac{Number\text{ }of\text{ }favourable\text{ outcomes}}{Total\text{ }Number\text{ }of\text{ }favourable\text{ outcomes}}$
Complete step by step answer:
Now, let’s discuss the problem.
Do you play with cards? If not then let’s know about these cards. You can play interesting games with these cards. The whole deck consists of 52 cards. It contains 4 suits each having 13 cards in it. These are spades, hearts, diamonds and clubs. Colour of spades and clubs are black while hearts and diamonds are red. Now, if we talk about one particular suit, it contains ace, king, queen, jack or knaves, 10, 9, 8, 7, 6, 5, 4, 3, and 2. The cards of King, Queen, and Jack (or Knaves) are called the face cards. So, in the whole deck, there are 12 face cards. Now, we will know what is probability and how it is applied on this deck of cards. Probability shows how likely an event can happen or we can say that how many chances are there for an event to take place. Probability of an event is given as:
P(any event E) = $\dfrac{Number\text{ }of\text{ }favourable\text{ outcomes of E}}{Total\text{ }Number\text{ }of\text{ }favourable\text{ outcomes of E}}$
For this question,
There are four cards for number ‘two’ that means there are four ways of getting two. So the total number of ways in which this event can occur is 4. And we already know that the total number of cards in a deck is 52. So 52 will be the total favourable outcomes. So,
P(getting two) = $\dfrac{4}{52}=\dfrac{1}{13}$
This is the final answer.
Note:
We have to find the probability of two from 52 cards not 13 cards. Students usually make such mistakes because they think that each suit contains 13 cards so probability will also be found for 13 cards itself. After applying formula, reduce the fraction in the simplest form. And do remember that the probability of any event cannot be greater than 1 and it also cannot be negative.
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