Question

How many yards are in a \[\dfrac{1}{4}\] of a mile?

Answer 1

Hint: In this question, we will use the concept of the conversion factor to convert miles to yards. As we know that yards and miles are the measuring units of distance and miles are used to measure the larger distance as compared to the yards.

Complete step by step answer:
In this question, we have given $\dfrac{1}{4}$ mile and we need to convert it into yards.
Before solving the problem, we want to know about miles and yards.
There are several units that are used to measure the length like meter, feet, yard, and mile, etc. The mile and yard are defined below:
Mile: it is the unit of length, which is British imperial units and United state customary units. Mile is most commonly equal to \[1609\;{\text{meters}}\], \[{\text{5280}}\;{\text{feet}}\] and \[{\text{1760}}\;{\text{yard}}\] . The symbol for miles is ‘mi’.
Yard: it is the unit of length, which is in several different systems including former English units, United States customary units, and the imperial units. Yard is equal to \[{\text{0}}{\text{.9144 meters}}\], \[{\text{3 feets}}\] and \[{\text{36 inches}}\]. The symbol for the yard is ‘yd’.
Now we come to the question,
In the question, the value of yard is given as \[\dfrac{1}{4}\].
Then we find the value of the yard.
The formula for calculating the value of yard from mile is given as below.
\[ \Rightarrow value{\text{ }}of{\text{ }}yard = \left( {value{\text{ }}of{\text{ }}mile} \right) \times 1760\]
Now we will substitute the value of mile in the above formula for calculating the value of yard.
Hence,
\[value{\text{ }}of{\text{ }}yard = \left( {\dfrac{1}{4}} \right) \times 1760\]
After solving we will get,
\[\therefore value{\text{ }}of{\text{ }}yard = 440\]

Therefore, in \[\dfrac{1}{4}\] mile the value of the yard is \[440\].

Note: As we know that there are several units of length like feet, meter, inches, yard, and mile, etc. in different systems. These units are connected to one another. And, easily convert one to another form.