$y$ is directly proportional to $x$ . Write an equation that shows the relationship if $x = 2$ and $y = 6$ ?
Answer
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Hint: To solve such problems always remember that directly proportional means $y = Kx$ where $K$ is any constant. Here the equation can be formed by substituting the values of $x$ and $y$ in $y = Kx$ . This will give the value of the constant and thus the equation.
Complete step-by-step solution:
Given that $y$ is directly proportional with $x$ . That is,
$y = Kx$ where $K$ is any constant.
Also given that $x = 2$ and $y = 6$ .
Substitute this in $y = Kx$ . That is,
$6 = K \times 2$
$K = 3$
Therefore, the value of the constant is $K = 3$ .
Hence the equation that shows the relationship if $x = 2$ and $y = 6$ is as shown below
$y = 3x$.
Additional Information: Suppose that there are two quantities $x$ and $y$ . If these two quantities increase or decrease at a constant rate then they are said to be directly proportional. If $x$ and $y$ are directly proportional then it can be written as $x{\text{ }}\alpha {\text{ }}y$ . Here $\alpha$ means proportional to.
If an increase in $x$ causes a decrease in $y$ or vice versa then the quantities are said to be in inverse proportion. If $x$ and $y$ are inversely proportional then it can be written as $x{\text{ }}\alpha {\text{ }}\dfrac{1}{y}$ . If $y$ is inversely proportional to $x$ , then it can be written as $y = \dfrac{K}{x}$ , where $K$ is any constant. Here $K$ is called the constant of proportionality of the relationship.
Note: Always remember that if the question says $y$ is directly proportional to $x$ , then it means $y$ will be a constant multiple of $x$ . It can also be said that if $y$ is directly proportional to $x$ , then $\dfrac{y}{x} = K$ or $y = Kx$ . If ${x_1},{x_2}$ are the values corresponding to $x$ and ${y_1},{y_2}$ are the values corresponding to $y$, also if $y$ is directly proportional to $x$ , then $\dfrac{{{y_1}}}{{{x_1}}} = \dfrac{{{y_2}}}{{{x_2}}}$ .
Complete step-by-step solution:
Given that $y$ is directly proportional with $x$ . That is,
$y = Kx$ where $K$ is any constant.
Also given that $x = 2$ and $y = 6$ .
Substitute this in $y = Kx$ . That is,
$6 = K \times 2$
$K = 3$
Therefore, the value of the constant is $K = 3$ .
Hence the equation that shows the relationship if $x = 2$ and $y = 6$ is as shown below
$y = 3x$.
Additional Information: Suppose that there are two quantities $x$ and $y$ . If these two quantities increase or decrease at a constant rate then they are said to be directly proportional. If $x$ and $y$ are directly proportional then it can be written as $x{\text{ }}\alpha {\text{ }}y$ . Here $\alpha$ means proportional to.
If an increase in $x$ causes a decrease in $y$ or vice versa then the quantities are said to be in inverse proportion. If $x$ and $y$ are inversely proportional then it can be written as $x{\text{ }}\alpha {\text{ }}\dfrac{1}{y}$ . If $y$ is inversely proportional to $x$ , then it can be written as $y = \dfrac{K}{x}$ , where $K$ is any constant. Here $K$ is called the constant of proportionality of the relationship.
Note: Always remember that if the question says $y$ is directly proportional to $x$ , then it means $y$ will be a constant multiple of $x$ . It can also be said that if $y$ is directly proportional to $x$ , then $\dfrac{y}{x} = K$ or $y = Kx$ . If ${x_1},{x_2}$ are the values corresponding to $x$ and ${y_1},{y_2}$ are the values corresponding to $y$, also if $y$ is directly proportional to $x$ , then $\dfrac{{{y_1}}}{{{x_1}}} = \dfrac{{{y_2}}}{{{x_2}}}$ .
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