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Write the natural numbers from 2 to 12. What fraction of them are prime numbers?

Answer
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511.5k+ views
Hint: In this problem, we have to find the natural numbers from 2 to 12 and we can find what fraction of them are prime factors. We know that natural numbers are a part of the number system, including all positive integers from 1 till infinity and also used for counting purposes and the prime number are the positive integers having only two factors, 1 and the integer itself. We can now find the required solution.

Complete step-by-step answer:
Here we have to find the natural numbers from 2 to 12 and we can find what fraction of them are prime factors.
We know that natural numbers from 2 to 12 are,
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12.
Here we have 11 given natural numbers.
We know that prime numbers are the positive integers having only two factors, 1 and the integer itself.
In the above given natural numbers, the prime numbers which have only two factors, 1 and the integer itself are,
2, 3, 5, 7, 11.
Here we have 5 prime numbers out of 11 natural numbers from 2 to 12.
Which we can write as,
\[\Rightarrow \dfrac{5}{11}\]
Therefore, the natural numbers from 2 to 12 are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 and \[\dfrac{5}{11}\] of them are prime numbers.

Note: We should always remember that the natural numbers are a part of the number system, including all positive integers from 1 till infinity and also used for counting purposes and the prime numbers are the positive integers having only two factors, 1 and the integer itself.

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